Question

What is the area of a rectangle that is \dfrac1{2} 2 1 ​ start fraction, 1, divided by, 2, end fraction of a meter long and \dfrac38 8 3 ​ start fraction, 3, divided by, 8, end fraction of a meter wide?

Answer 1

Answer:

$Area = \frac{3}{16} m^2$

Step-by-step explanation:

Given

Shape: Rectangle

$Length = \frac{1}{2}\ m$

$Width = \frac{3}{8}\ m$

Required

Determine the area of the rectangle;

Area is calculated as thus;

$Area = Length * Width$

Substitute values for Length and Width

$Area = \frac{1}{2} * \frac{3}{8}$

$Area = \frac{1 * 3}{2 * 8}$

$Area = \frac{3}{16}$

Hence, the area of the rectangle is $\frac{3}{16}m^2$