Answer:
0.001953125
Step-by-step explanation:
Divide 34 by 512
34 ÷ 512 = 0.06640625
divide 0.06640625 by 34
0.06640625 ÷ 34 = 0.001953125
Check you work
34 × 0.001953125 = 0.06640625
Answer is 3 4 ÷ 5 12 = 3 4 × 0.001953125
R=16
J=32
20+40(which is 20×2)=60
20-4=16
16×2=32
Answer:
<em>Jane traveled 8 miles farther then her trainer</em>
Step-by-step explanation:
<u>The Pythagora's Theorem</u>
In any right triangle, the square of the measure of the hypotenuse is the sum of the squares of the legs. This can be expressed with the formula:

Where
c = Hypotenuse or largest side
a,b = Legs or shorter sides
Jane's path from the Health Club to the end of her route describes two sides of a right triangle of lengths a=16 miles and b=12 miles.
Her total distance traveled is 16 + 12 = 28 miles
Her trainer goes directly from the Health Club to meet her through the hypotenuse of the triangle formed in the path.
We can calculate the length of his route as:


c = 20 miles
The difference between their traveled lengths is 28 - 20 = 8 miles
Jane traveled 8 miles farther then her trainer
Piecewise Function is like multiple functions with a speific/given domain in one set, or three in one for easier understanding, perhaps.
To evaluate the function, we have to check which value to evalue and which domain is fit or perfect for the three functions.
Since we want to evaluate x = -8 and x = 4. That means x^2 cannot be used because the given domain is less than -8 and 4. For the cube root of x, the domain is given from -8 to 1. That meand we can substitute x = -8 in the cube root function because the cube root contains -8 in domain but can't substitute x = 4 in since it doesn't contain 4 in domain.
Last is the constant function where x ≥ 1. We can substitute x = 4 because it is contained in domain.
Therefore:
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 8} \\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%208%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
The nth root of a can contain negative number only if n is an odd number.
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 2 \times - 2 \times - 2} \\ f(4) = 3 \end{cases}} \\ \large{ \begin{cases} f( - 8 ) = - 2\\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%202%20%5Ctimes%20-%20%202%20%5Ctimes%20%20%20-%202%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D%20%5C%5C%20%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20-%202%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
Answer
I think it's the third one b/c
the associative property states that it doesn't matter how you group the
numbers in parenthesis in addition.