Deposition<span> is a </span>thermodynamic process<span>, a </span>phase transition<span> in which </span>gas<span> transforms into </span>solid<span> without passing through the </span>liquid phase<span>. The reverse of deposition is </span>sublimation sublimation is cooling hope this helps!!
Answer:
25.5 g
Explanation:
First, you will need a balanced chemical equation
CuO + H₂ ==> H₂O + Cu
From the equation above, we can see that for every 1 mole of CuO (copper(II) oxide), 1 mole of Cu (copper) is produced.
Convert grams of CuO to moles. You should get 0.402 mol. Now with the relationship established above, you can see that you should ideally get 0.402 mol. Convert this to grams. Your answer should be 25.5 g.
HCl is an acid, C5H5N is a base, Cl is an acid, and HC5H5N is an acid.
Hope this helps! If so, brainliest would be appreciated!
3 mole of O2 produce=2 iron oxide
0.5 of O2 produce=x
0.5 X 2/3
X=0.33 mole of iron oxide
Answer:
38.9%
Explanation:
below, determine the mass percent of Fe3+ in a 0.6450 g sample of iron ore, if 22.40 mL of a 0.1000 M stannous chloride, SnCl2(aq), solution is required to completely react with the Fe3+ present in the ore sample. The chemical equation for the reaction is
2 Fe3+ (aq) + Sn2+ (aq) →2Fe2+ (aq) + Snº+(aq).
O 19.40%
O 6.196%
O 38.79%
O 9.697%
2 Fe3+ (aq) + Sn2+ (aq) →2Fe2+ (aq) + Snº+(aq).ole of Sn2+
for every mole of Sn2+, tere are 2 moles of Fe3+
- 22.4/1000L of 0.1000 M Sn2+ = 22.4 X 0.10/1000 = 0.00224 mole
so there are 0.00224 X 2= 0.00448 moles Fe3+
iron atomic mass is 56
56 X 0.00448 = 0.251 gm Fe3+
so the mass % of the Fe3+ in the 0.645 gm iron ore sample is
(0.251/0.645) X 100 = 38.9%
