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Valentin [98]
3 years ago
7

In a car piston shown above, the pressure of the compressed gas (red) is 5.00 atm. If the area of the piston is 0.0760 m^2. What

is the force exerted on the piston in Newtons (N)?
Chemistry
1 answer:
Shkiper50 [21]3 years ago
6 0

Answer:

38503.5N

Explanation:

Data obtained from the question include:

P (pressure) = 5.00 atm

Now, we need to convert 5atm to a number in N/m2 in order to obtain the desired result of force in Newton (N). This is illustrated below:

1 atm = 101325N/m2

5 atm = 5 x 101325 = 506625N/m^2

A (area of piston) = 0.0760 m^2

Pressure is force per unit area. Mathematically it is written as

P = F/A

F = P x A

F = 506625 x 0.0760

F = 38503.5N

Therefore, the force exerted on the piston is 38503.5N

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La valencia que utiliza el hidrógeno al formar un hidruro metálico es
Serjik [45]

Answer: Esta tendencia es tan regular que el poder de combinación, o valencia, de un elemento se definió una vez como el número de átomos de hidrógeno unidos al elemento en su hidruro. El hidrógeno es el único elemento que forma compuestos en los que los electrones de valencia están en la capa n = 1.

Explanation:

¡Espero que esto ayude!

4 0
3 years ago
9. What type of bond is pictured in the image below?
mestny [16]

Answer:

metallic bond

because this diagram is electron gas theory which shows metallic bond

8 0
2 years ago
What is Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium
hram777 [196]

The Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium concentrations are Keq = 1.5. The correct option is D.

<h3>What is Keq?</h3>

Keq is the ratio of the concentration of reactant to the concentration of the product.

The balanced equation is

N₂ + 3H₂  = 2NH₃

The equilibrium constant is \rm \dfrac{[NH_3]^2}{[N_2]\; [H_2]^3}

The given concentrations of the compounds have been:

Ammonia = 3 M

Nitrogen = 1 M

Hydrogen = 2 M

\rm \dfrac{9}{1\times 8} = 1.5

Thus, the correct option is D. Keq = 1.5.

Learn more about Keq

brainly.com/question/24059926

#SPJ1

3 0
2 years ago
Give the IUPAC name for the following structure: 3-chloro-6-methylcyclohexanol 2-methyl-5-chlorocyclohexanol 1-chloro-4-methylcy
Shtirlitz [24]

Answer:

5-chloro-2-methylcyclohexanol    

Explanation:  

There is no structure for the compound, but we can analyze the proposed options using the IUPAC rules to name organic compounds.  

IUPAC rules state that to name an organic compound, first we have to identify the priorities for the functional groups present in the compound. <em><u>In this case, the priority functional group is the alcohol group</u></em>, <u><em>so we will start the counting of the carbons in this group.</em></u> Then, the counting of carbon atoms is followed by the next substituents so they have the lowest possible numbers, <em><u>in this case, we can assign the number 2 to the methyl group and 5 to the chloride group</u></em>, and name the compound in alphabetical order, using commas to separate the words from the numbers and with no space between the words.                      

Since the other options involve: <u>high countings for the susbtituents groups  (</u><u>3</u><u>-chloro-</u><u>6</u><u>-methylcyclohexanol)</u>, <u>wrong assignation of priority functional group (</u><u>1-chloro</u><u>-4-methylcyclohexanol), wrong sequence of counting in the compound (</u><u>2-methyl-3-chloro</u><u>cyclohexanol) and no alphabetical order to name the compound (2-</u><u>methyl</u><u>-5-</u><u>chloro</u><u>cyclohexanol), </u><u>the correct option is:</u>            

5-chloro-2-methylcyclohexanol  

Have a nice day!

4 0
3 years ago
PLEASE HELP I NEG YOU FATHERCARRAS PLEASE HELP ME !!!
LekaFEV [45]
Answer 
<span>How does adding a non-volatile solute to a pure solvent affect the vapor pressure of the pure solvent?

</span>Answer The third option The solvent's vapor pressure will not be affected.

<span>To make a 2.0 M solution, how many moles of solute must be dissolved in 0.50 liters of solution?

Answer C. 1.0 mole solute.
</span>
3 0
3 years ago
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