Answer:
pH = 8.92
Explanation:
To solve this question we must know that the reaction of KOH with HC3H5O2 is:
KOH + HC3H5O2 → H2O + KC3H5O2
At equivalence point, all propanoic acid reacts to produce KC3H5O2.
This KC3H5O2 = C3H5O2⁻ is in equilibrium in water as follows:
C3H5O2⁻(aq) + H₂O(l) → OH⁻(aq) + HC3H5O2(aq)
<em>Where Kb = Kw / ka = 1x10⁻¹⁴/ 1.34x10⁻⁵ = 7.46x10⁻¹⁰</em>
is defined as:
Kb = 7.46x10⁻¹⁰ = [OH⁻] [HC3H5O2] / [C3H5O2⁻]
As both [OH⁻] [HC3H5O2] ions comes from the same equilibrium,
[OH⁻] = [HC3H5O2] = X
[C3H5O2⁻] is:
<em>Moles KOH = Moles </em>C3H5O2⁻:
0.0325L * (0.15mol / L) = 0.004875 moles
In 32.5 + 20mL = 52.5mL = 0.0525L:
0.004875 moles / 0.0525L = 0.09286M.
Replacing:
7.46x10⁻¹⁰ = [X] [X] / [0.09286M]
6.927x10⁻¹¹ = X²
X = 8.323x10⁻⁶M = [OH-]
As pOH = -log [OH-]
pOH = 5.08
pH = 14 -pOH
<h3>pH = 8.92</h3>
You find the molar mass of NaCl first, by adding the weight of both to get 58.44g.
Then you set up the equation with what is given:
2.4mol NaCl and multiply it by 58.44g NaCl to get your answer= 140.256g
Answer:
<h2>2 m</h2>
Explanation:
The wavelength of a wave can be found by using the formula
where
c is the speed of the wave
f is the frequency
From the question
c = 5 m/s
f = 2.5 Hz
We have
We have the final answer as
<h3>2 m </h3>
Hope this helps you
Answer:
Glucose would not be able to get into the cell treated with this chemical
Potassium mwill not be able to move or transport may be affected
Explanation:
As all membrane transport proteins are inactivated glucose is abig molecule it cannot pass without transporter protein.
Potassium transport is through sodium potassium pump and leak channels. As all transport protein are affected so it should not be able to move but if drug does not affect them then they will be unaffected.
When cohesive force is stronger than the adhesive force: concave up meniscus, water forms droplets on surface
