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3 years ago

Please help me solve this

Mathematics

2 answers:

maksim [4K]3 years ago

5 0

The correct answer is D

Lena [83]3 years ago

4 0

Answer:

gergvv

Step-by-step explanation:

rvgfc erbvgcft ebh t

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If this money were equally distributed among the world's population of 7.0 billion people, how much would each person receive?

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3 years ago

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oksian1 [2.3K]

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144

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A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function =ht−64t16t2. What is the ma

ryzh [129]

This is the concept of applications of polynomial equations. Given that the height of the ball is modeled by the function:
h(t)=16t^2-64t
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3 years ago

10 points!!! please help :(

daser333 [38]

To complete the identity, we need these fundamental identities:

$1)\displaystyle{sec(x)=\frac{1}{cos(x)}$

$2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)$

$\displaystyle{csc(x)= \frac{1}{sin(x)}$

Thus, by identity 1 we have:

$\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}$

by identity :

$\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)$

recall the values :

$\displaystyle{ sin(\frac{ \pi }{2})^R=sin(90^o)=1\\\\$

$\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0$ ,

so:

$cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)=0+sin(\theta)=sin(\theta)$

Putting all these together, we have:

$\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}$

which is equal to $csc(\theta)$ , by identity 3

Answer: D

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