Company A has a sales position with a yearly salary of $42,000. Company B has a similar sales position with a slary of $39,000 plus 1% conmission on yearly sales.
Let x be the amount of yearly sales
Company A has a sales position with a yearly salary of $42,000.
yearly salary = 42,000
Company B has a similar sales position with a salary of $39,000 plus 1% commission on yearly sales.
1% is 0.01
yearly salary = 39,000+ 0.01x
yearly sales is the salary at company A greater than the salary and conmission at company B
A > B
42000 > 39000+ 0.01x
We solve the inequality
39000+ 0.01x < 42000
Subtract 39000 on both sides
0.01x < 3000
divide by 0.01
x> 300,000
For yearly sales > $300,000, the salary at company A greater than the salary and commission at company B
The standard deviation shows the dispersion (how close) of the data. Therefore the correct statement is A:
<span>A- Raquel’s data are most likely closer to $3.42 than Van’s data are to $3.78.</span>
1st term = -10
2nd term = -6
3rd term = -2
4th term = 2
5th term = 6
6th term = 10
7th term = 14
The reason how I got 14 for the 7th term is because, i added 4 to each term.
Hope this helps!
