All categories

3 years ago

Find the distance around a rectangle with width of 8 and a length of 29

Mathematics

2 answers:

madam [21]3 years ago

8 0

Answer:

Step-by-step explanation:

hope it helps

jekas [21]3 years ago

4 0

Answer:

Step-by-step explanation:

Distance of rectangle=h+w+h+w or 2h+2w

=2*8+2*29

=16+58

=74

Hope it's helpful to you

You might be interested in

Prove that: (secA-cosec A) (1+cot A +tan A) =( sec^2A/cosecA)-(Cosec^2A/secA)<br>

Ksju [112]

Step-by-step explanation:

$(\sec A - \csc A)(1 + \cot A + \tan A)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)$

$=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)$

$=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)$

$=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}$

$=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}$

$=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}$

$=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}$

$=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)$

$=\sec^2A\csc A - \csc^2A\sec A$

5 0

3 years ago

The population of a city increases by 4,00 people each year. in 2025 the population is projected to be 450,000 people. what is a

Sedbober [7]

P=4x+40.......................................

7 0

4 years ago

Please help me :)!!!!!!!!!!!!!

ivolga24 [154]

A root is where the line crosses the x axis. This line crosses the x axis 3 times so the answer is B..

5 0

3 years ago

Grandma has 4 bags of soil for her flower pots each flower pot needs 3/4 of a bag of soil how many flower pots can she fill

Ostrovityanka [42]

Answer:

she can fill 5 pots and have 1/3 bag left over

Step-by-step explanation:

4 0

3 years ago

Help help i really need it asap

dimaraw [331]

Answer: c

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers