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user100 [1]
3 years ago
12

A box is in the shape of a rectangular prism. Nicole is trying to ship boxes of her homemade peanut butter cookies. The box she

is using to ship has the dimensions of 10in by 10in by 12in. Each cookie box has dimensions of 2in by 5in by 3in. How many cookie boxes will fit into the box to be shipped? Explain how you got your answer.
Mathematics
2 answers:
makvit [3.9K]3 years ago
5 0

Answer:

Number of cookie boxes will fit into the large box  = 40

Step-by-step explanation:

Length breadth and height are given in order.

Size of large box = 10 in x 10 in x 12 in

Size of small box = 2 in x 5 in x 3 in

Complete volume of large box can be utilized since length breadth and height of large box is multiple of small box.

Volume of large box = 10 x 10 x 12 = 1200 in³

Volume of small box = 2 x 5 x 3 = 30 in³

Number of cookie boxes will fit into the large box  

                 =\frac{\texttt{Volume of large box}}{\texttt{Volume of small box}}=\frac{1200}{30}=40

Number of cookie boxes will fit into the large box  = 40

Katyanochek1 [597]3 years ago
4 0

<span>So L = x-4, W = x-4, H = x 
  
Volume = length * width * height 
 
V = L * W * H 
 
V = (x-4)*(x-4)*x 
 
V = ???

</span>x is the height, so x-4 is the length and also the width since <span>length and a width of 4in. less than the height</span>
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Answer:

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If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.  

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Data given and notation  

The mean and sample deviation can be calculated from the following formulas:

\bar X =\frac{\sum_{i=1}^n x_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)}{n-1}}

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s=1.365 represent the sample standard deviation  

n=6 sample size  

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\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

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Alternative hypothesis:\mu < 30  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17  

P-value  

We need to calculate the degrees of freedom first given by:  

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p_v =P(t_{(5)}  

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If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.  

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

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