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kherson [118]
3 years ago
13

Find the unkown angle of a triangle​

Mathematics
1 answer:
REY [17]3 years ago
6 0

Step-by-step explanation:

Find

Triangle A(because there are two triangles)

take 28°+39°=67°

an angle is 180° in total so you take

180°-67°=113°

Angle x = 113°

Angle y = 67°

Triangle B

64°+67° = 131°

180°-131°=49°

Angle z =49°

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crimeas [40]
The answer is 70 i believe
3 0
3 years ago
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A Rectangle is removed from a right triangle to create the shaded region below. Find the area of the shaded region be sure to in
Scorpion4ik [409]

The given shapes area is found to be 4 square yards.

Step-by-step explanation:

Step 1; To determine the area of an indefinite shape we must divide it into the shapes that we know. The shape that is given can be split into a triangle with a rectangle in it.

Step 2; Any given triangles area is half the multiplication of its base value and its height value. In the given diagram, the base of the triangle measures a length of 5 yards and the length from base to top is 4 yards

Area of the triangle = \frac{1}{2} * base * height = \frac{1}{2} * 5 * 4 = 10 square yards.

The given rectangle measures a length of 3 yards and a width of 2 yards. The area of any given rectangle is the multiplication of its length and width.

Area of the rectangle = Length * Width = 3 yards * 2 yards = 6 square yards.

Step 3; To find the total area of the shape we must subtract the the rectangle's area from the triangle's area.

Area of given shape = Area of the triangle - Area of the rectangle.

Area of given shape = 10 square yards - 6 square yards = 4 square yards.

7 0
3 years ago
Eight more than the quotient of a number and 4 equals 5
Lady bird [3.3K]
Well we can put that word problem into a equation so, 8+x/4=5. Now what I would do is move the 8 to the other side, and since it moved to the other side it becomes a -8 so now we have x/4 = -3. Now I would multiply both side by 4 to get x = -12

Answer= X = -12
3 0
3 years ago
Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt
Paladinen [302]

Answer:

y(x)=4a\sqrt{3}* sin(x)-3a

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}

But:

\frac{1}{tan(x)} =cot(x)

So:

\frac{dy(x)}{dx} =cot(x)*(3a+y)

Multiplying both sides by dx and dividing both sides by 3a+y:

\frac{dy}{3a+y} =cot(x)dx

Integrating both sides:

\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx

Evaluating the integrals:

log(3a+y)=log(sin(x))+C_1

Where C1 is an arbitrary constant.

Solving for y:

y(x)=-3a+e^{C_1} sin(x)

e^{C_1} =constant

So:

y(x)=C_1*sin(x)-3a

Finally, let's evaluate the initial condition in order to find C1:

y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a

Solving for C1:

C_1=4a\sqrt{3}

Therefore:

y(x)=4a\sqrt{3}* sin(x)-3a

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4 years ago
Plz help ASAP 20 points 5. In circle A, the length of arc BC is 20π units.
Verdich [7]

Answer: i think the answer is B or C sorry

Step-by-step explanation:

have a nice day

5 0
3 years ago
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