Question

Solve for x. whats the solutions from least to greatest. 4x^2 + 48x + 128 = 0

Answer 1

Answer:

$\boxed{\sf \ \ \ x = -8 \ or \ x = -4 \ \ \ }$

Step-by-step explanation:

Hello,

$4x^2+48x+128=0\\ 4(x^2+12x+32)=0\\ x^2+12x+32=0\\ (x+6)^2 - 36 + 32= 0\\\\ (x+6)^2-4=0\\ (x+6+2)(x+6-2)=0\\ (x+8)(x+4) = 0\\ x = -8 \ or \ x = -4$