Answer:
The distance between the pirate and the treasure can be found from the following relationship between ΔEAF and ΔABC;
/
=
/
=
/
Step-by-step explanation:
From the question diagram, we have two triangles, ΔEAF and ΔABC;
The ratio of the lengths of the sides /
=
/
∠EAF and ∠BAC are vertical angles, therefore ∠EAF = ∠BAC
Therefore, ΔEAF and ΔABC are similar triangles by Side-Angle-Side, SAS, rule of similarity which states that two triangles that have ratios of a pair of their corresponding sides and the two sides also form equal angles within each triangle, then the two triangles are similar
Therefore, the ratio of the each pair of corresponding sides of the two triangles are equal
We have;
/
=
/
= 50 ft. /(100 ft.) =
/
=
/120 ft.
= 120 ft. × 50 ft./(100 ft.) = 60 ft.
= 60 ft.
The distance between the pirate and the treasure, = 60 ft.