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taurus [48]
4 years ago
11

A 275 inch pipe is cut into two pieces. One piece is four times the length of the other. Find the length of the shorter piece.

Mathematics
1 answer:
Darina [25.2K]4 years ago
3 0

Since one piece is four time the length <em>x, </em>we can represent that as 4x.

Thus making the equation:

4x+x=275

5x=275

x=55

4(55)=220

220+55=275

So, the length of the longer piece is 220 inches, and the length of the shorter piece is 55 inches.

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charlie wants to order lunch for his friends he'll order 5 sandwiches and a $3 kid's meal for his little brother charlie has $28
ASHA 777 [7]

Answer:

if everything cost the same thing you have to do 3x5 to get the answer so

3x5=$15 + the $3 kids meal sot the answer is 18. and eand up with 10$

Step-by-step explanation:

5 0
3 years ago
If a &gt; b &gt; c &gt; d, then which is larger, a+c or b+d ? Can we tell from a &gt; b &gt; c &gt; d which of a+d and b+c is la
victus00 [196]

Answer:

1. a+c is larger than b+d

2. No way to tell whether a+d or b+c is larger.

Step-by-step explanation:

<u>1. Which is larger, a+c or b+d?</u>

Let a, b, c, and d be any numbers such that a > b > c > d.

Specifically, note that a > b, and subtracting b from both sides of the inequality, observe that a-b > 0.

Similarly, c > d, and subtracting d from both sides of the inequality, observe that c-d > 0.

From this, <u>add "a-b"</u> (a positive number, as proven above) to both sides of the inequality.

(a-b)+(c-d) > (a-b)+0

Addition by zero (<u>the additive identity</u>) doesn't change anything, so the right side remains "a-b"...

(a-b)+(c-d) > a-b

... and <u>"a-b" is positive</u>...

(a-b)+(c-d) > a-b > 0

... so, by the <u>transitive property</u> of inequality...

(a-b)+(c-d) > 0

Recall that <u>subtraction is addition by a negative</u> number...
a+(-b)+c+(-d) > 0

...and that <u>addition is associative and commutative</u>, so things can be added in any order, so the middle two terms on the left side can be rearranged...

a+c+(-b)+(-d) > 0

<u>Adding b + d</u> to both sides of the inequality

(a+c+(-b)+(-d))+(b+d) > 0+(b+d)

... and <u>simplifying</u>

a+c > b+d

So, a+c is larger than b+d.

<u>2. Which is larger, a+d or b+c?</u>

Consider the following two examples:

<u>Example 1</u>

Suppose a=10; b=3; c=2; d=1.

Note that a > b > c > d (10 > 3 > 2 > 1) and, also observe that a+d=(10)+(1)=11, and b+c=(3)+(2)=5, so a+d is larger than b+c.

<u>Example 2</u>

However, suppose a=10; b=9; c=8; d=1.

Note that a > b > c > d (10 > 9 > 8 > 1) but that a+d=(10)+(1)=11, and b+c=(9)+(8)=17, so a+d is smaller than b+c.

So, in one example, a+d is bigger, and in the other, a+d is smaller.  Therefore, there is no way to tell which of a+d or b+c is larger from only the given information.

5 0
2 years ago
Select the correct answer.
natulia [17]

Answer:

B

Step-by-step explanation:

just think about it :

can it move up or down ? no, because for a specific input value still the same functional result is calculated (nothing is getting bigger or smaller).

all that is happening that way is that now, with using g(x), the original f(x) functional values happen now 2 units "later" = to the right (if you consider the x-axis a time line growing to the right). we are getting the functional value of f(x-2) at x and not at x-2 for g(x).

for example

the functional values are for x² (just some integers to make it easier) :

x = 1, 2, 3, 4, 5, ...

getting

f(1), f(2), f(3), f(4), f(5), ...

leading to

1², 2², 3² 4², 5², ...

which is

1, 4, 9, 16, 25, ...

now, let's say we start looking at x = 3

x = 3, 4, 5, 6, 7, ...

getting

g(3), g(4), g(5), g(6), g(7), ..

leading to

1², 2², 3² 4², 5², ...

which is

1, 4, 9, 16, 25, ...

so, now we are getting the functional value at e.g. x = 5 that we got originally for x = 3 (9).

therefore, under g(x) the original functional values still "happen", they just simply "happen" 2 units "later" (to the right).

in the same way

g(x) = f(x+2) moves everything 2 units to the left (now things are happening "earlier").

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Step-by-step explanation:

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