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hjlf
3 years ago
12

PLZ HELP ASAP INSCRIBED SHAPES

Mathematics
2 answers:
OverLord2011 [107]3 years ago
8 0
The radius is the hypotenuse of the eight triangle. So we can use pythagorean triples to find the side.

It’s handy to remember that 5, 12, 13 is a pythagorean triple.

So, 13 is the radius.

Hope this helped!
prohojiy [21]3 years ago
7 0
The radius of circle O is the same as half of the hypotenuse of the right triangle.

The find the hypotenuse, simply use the following,

\sqrt{a { }^{2} + b ^{2} }

Or the square root of one leg squared us the other leg squared.

I already know this to be a 5 - 12 - 13 right triangle and you can get 13 with the equation.

~~

Half of 13 is 6.5 meaning 6.5 is our radius.

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey
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Three vertices of a rectangle have coordinates (–6, 2), (–6,–1), and (4, 2).
Allushta [10]
The correct answer would be C., I believe, because you take the opposite of the coordinate and subtract one. Hope this was helpful! (:
5 0
4 years ago
See question in attached photo.<br>Answer question 4b and 5c​
sdas [7]

9514 1404 393

Answer:

  4b: 8.6 m/s²; 1.3×10^5 N; 2.1×10^4 N decrease

  5c: -1.6×10^12 J; -1.6×10^12 J

Step-by-step explanation:

<h3>4b</h3>

i) The acceleration due to gravity is inversely proportional to the square of the distance between the objects. The distance to the shuttle is ...

  1 + (5×10^5)/(6.4×10^5) = 69/64 . . . times the radius of the earth

Then the acceleration due to gravity at the height of the space shuttle is about ...

  (10 m/s²)(64/69)² ≈ 8.6 m/s²

__

ii) The weight of the space shuttle at that height is about ...

  F = ma = (15000 kg)(8.6 m/s²) ≈ 1.3×10^5 N

__

iii) The loss of weight will be ...

  ΔF = m(a1 -a0) = (15000 kg)(10 m/s² -8.6 m/s²)

  = 1.5×10^4×1.4 N = 2.1×10^4 N

____

<h3>5c</h3>

i) The gravitational potential energy is given by ...

  U = -GMm/r

where M and m are the mass of the earth and the rocket, respectively.

  U = -(6.67×10^-11)(6.0×10^24)(2.5×10^4)/(6.4×10^6) ≈ -1.6×10^12 J

__

ii) At a height of 3×10^4 m, the denominator in the above expression changes from 6.4×10^6 to 6.43×10^6. This changes the gravitational potential energy by a factor of 6.4/6.43 to -1.6×10^12 J

(Note: we're carrying only 2 significant figures in the result in accordance with the rules for precision in such calculations. The change is noticeable at the level of the 4th significant figure, less than 1/2%.)

4 0
3 years ago
Lines k and n are perpendicular.if the slope of line k is -6,what is the slope of line n?
aleksley [76]

Answer:

1/6

Step-by-step explanation:

Well perpendicular lines are reciprocals of each other,

meaning if like k has a slope of -6 then line n will have a slope of positive 1/6.

<em>Thus,</em>

<em>line n has a slope of 1/6.</em>

<em />

<em>Hope this helps:)</em>

3 0
3 years ago
Read 2 more answers
What is the area of the
makvit [3.9K]

Answer:

D. 720cm squared is the answer

8 0
3 years ago
Solve the equation. –4y + 8 = 4(2y – 2) + 4(8 - 2y)
ss7ja [257]
-Y+2=(2y-2)+(8-2y) @
Y=-4
4 0
3 years ago
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