Answer:
Width of the rectangle = 5 inches
Length of the rectangle = 20 inches
Step-by-step explanation:
Let us assume the width of the rectangle = m in
So, the length of the rectangle = 4 (Width) = (4 m) in
Perimeter of the rectangle = 50 inches
Now, Perimeter of the Rectangle = 2 (LENGTH + WIDTH)
⇒ 2( m + 4m) = 50
or, 2(5m) = 50
⇒ 10m = 50 or, m = 50/10 = 5
⇒ m = 5
So, the width of the rectangle = 5 inches
and the length of the rectangle = 4 m = 4 x 5 = 20 inches
Answer:
m(∠AOF) = 148°
Step-by-step explanation:
From the figure attached,
CD intersects line EF at a point O.
Line CD is perpendicular to the line EF.
m(∠AOE) = 32°
m(∠COE) = 90°
Since m(∠COE) = m(∠AOE) + m(∠AOC) = 90°
32° + m(∠AOC) = 90°
m(∠AOC) = 90° - 32° = 58°
m(∠AOF) = m(∠AOC) + m(∠COF)
= 58° + 90°
= 148°
Therefore, m(∠AOF) = 148° will be the answer.
80+32=112 so all you do is just add or use a brain .
9514 1404 393
Answer:
10
Step-by-step explanation:
For c correct answers and 5 incorrect answers, James's score is ...
4c -2(5) = 30
4c = 40 . . . . . . add 10
c = 10 . . . . . . . . divide by 4
James gave 10 correct answers.
