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Taya2010 [7]
2 years ago
11

What is the value for y? Enter your answer in the box.

Mathematics
1 answer:
Anna007 [38]2 years ago
4 0

Answer:

y = 28

Step-by-step explanation:

since this is an Isosceles triangle (x - 5)° must be equal to 34°

x - 5 = 34

x = 39

the sum of interior angles in a triangle is equal to 180°

if the two angles 34 + 34 = 68

Then the third angle is 180 - 68 = 112°

4y = 112

y = 28

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Rich deposited money into a bank account that earned 2.5% simple interest each year. After 2 years, he had earned $14.65 in inte
photoshop1234 [79]

we know that


The simple interest formula is equal to


I=Prt


where


P is the Principal amount of money to be invested


I is the amount of money in interest

r is the rate of interest  

t is Number of Time Periods


in this problem we have


t=2\ years\\ I=\$14.65\\r=0.025


substitute in the formula above  and solve for P

14.65=P(0.025)(2)

P=14.65/[(0.025)(2)]

P=\$293


therefore

<u>the answer is</u>

\$293




5 0
3 years ago
Read 2 more answers
Multiply -3i and it’s conjugate. Simplify.
Alex_Xolod [135]

Answer:

-3 + 9i

Step-by-step explanation:

The conjugate of -3i is - 3 - i.

(- 3 i) × (- 3 - i)

Multiply both terms.

-3 + 9i

5 0
3 years ago
In a group of 10 ​kittens, 5 are female. Two kittens are chosen at random. ​a) Create a probability model for the number of male
olya-2409 [2.1K]

Answer:

(b) Expected number of male kitten E(x) = 1

(c) Standard deviation is ±\frac{2}{3}.

Step-by-step explanation:

Given that,

Number of kittens in a group are 10. Out of these 5 are female.

To find:- (a) create a probability model of male kitten chosen.

    So,  total number of kitten = 10

           number of female kitten = 5    

then, Number of male kitten = 10-5= 5

Now total number of ways to choosing two kittens from group of 10 = ^{10} C_{2}

                                                                                                                 = \frac{10!}{2!\times8!}

                                                                                                                 = 45

for choosing (i) No male P(x=0) = P(Two female) =  \frac{^{5} C_{2}}{45}

                                                                           = \frac{2}{9}

                     (ii) 1 male P(x=1) = P(1 male and 1 female) = \frac{^{5} C_{1}\times^{5} C_{1}}{45} =  \frac{25}{45} =\frac{5}{9}

                     (iii) 2 male P(x=2)= P(2 male) =\frac{^{5} C_{2}}{45} =  \frac{2}{9}

      x_{i}                             0                     1                      2

P(X=x_{i})                           \frac{2}{9}                      \frac{5}{9}                      \frac{2}{9}

(b) what is expected number of male kittens chosen ?

    Expected number of male kitten E(x) =  o\times \frac{2}{9} + 1\times \frac{5}{9} + 2\times\frac{2}{9}

                                                                  = 1

(c) what is standard deviation ?

                              \sigma(x) = \sqrt{ (E(x^{2} )-(Ex)^{2})

No,                          

                               Ex^{2} =o\times \frac{2}{9} + 1\times \frac{5}{9} + 4\times\frac{2}{9}

                                       = \frac{13}{9}

                               \sigma(x)=\sqrt{\frac{13}{9} - 1 }=\sqrt{\frac{4}{9} }  

                                       = ± \frac{2}{3}

                               

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It is too blurry to read please correct me if this is wrong question
a     =17,a      =3 is that what the question says?
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2 years ago
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