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AnnyKZ [126]
3 years ago
5

Which value is a solution of the equation 8y=56?

Mathematics
1 answer:
Korvikt [17]3 years ago
3 0

Answer:

7

Step-by-step explanation:

If you divide 8y / 8  then you have to do the same thing to 56. When you do, y  = 7

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PLSSSSS HURRY Brainliset involed
ExtremeBDS [4]

Answer:

24.36m²

Step-by-step explanation:

area = ½×(8.9+2.7)×4.2= ½×48.72=24.36m²

4 0
3 years ago
Ellie runs 5/6 mile in 10 minutes.what is ellie's speed in miles per minute?
olganol [36]

Answer:

1/12 miles/minute

Step-by-step explanation:

To figure out how fast ellie runs in 1 minute, we can set up this equation:

5/6 = 10x (x being the speed per minute)

We can divide both sides by 10

5/60 = x

Then simplify the fraction to get:

1/12 = x

4 0
3 years ago
Write an expression to represent:<br> Eight more than the product of two and a number number x
NARA [144]
Eight more than the product of two and a number x

8+2x <== in mathematical form

Eight more= 8+

Product= multiply

number=x

~'Manda
7 0
4 years ago
Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]
Anit [1.1K]

Answer:

The answer is "\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}".

Step-by-step explanation:

\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}

Solve the L.H.S part:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]

After calculating the L.H.S part compare the value with R.H.S:

\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\

\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\

In equation (i) multiply by 3 and subtract by equation (iii):

\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to  c= - \frac{1}{2}

put the value of c in equation (i):

\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\

In equation (ii) multiply by 3 then subtract by equation (iv):

\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\

put the value of d in equation (iv):

\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2

The final answer is "\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}".

4 0
4 years ago
Help someone if you not sleep please
mart [117]

Hello from MrBillDoesMath!

Answer:

+\- 10i

Discussion:

Fortunately, I can do this one in my sleep...... );


+\- sqrt(-100)  =

+\- 10 i                         where i = sqrt(-1)


Thank you,

MrB

8 0
3 years ago
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