Answer:
We can use linear system of equation with one variable.
Step-by-step explanation:
It is given that,Nina is 10 years younger than Deepak.
Deepak is 3 times as old as Nina.
<u>To solve this using linear equation</u>
Let d be the age of Deepak and n be the age of NIna
we can write,
n = (d - 10) ---(1)
d = 3n
d = 3(d - 10) --------(2)
d = 3d - 30
3d - d = 30
2d = 30
d = 30/2 = 15
n - d - 10 = 15 - 10 = 5
Therefore the age of Deepak = 15 and age of Nina = 5
Given:
circular pool with a diameter of 25 meters.
find: area of the bottom of the pool.
It is safe to assume that the diameter of the pool is the same from the top of the pool to the bottom of the pool.
Area of a circle = π r²
where:
π = 3.14
r = diameter / 2 = 25 meters / 2= 12.5 meters
Area of a circle = 3.14 * (12.5m)²
= 3.14 * 156.25 m²
Area of a circle = 490.625 m²
490.625 m² round to the nearest tenth is 490.60 m²
We round down because the number after 6 is 2. Whenever a number to be rounded off is followed by 0,1,2,3,and 4. Then, the number is rounded down.
Step-by-step explanation:
the price charged for 100 students reflects the cost per student that applies to the order as a whole.
100 * 6 = $600, so the fixed cost is 750-600 = 150.
...
We can check this by substituting in the other equation.
Does 150*6 + 150 = 1050?
150*6=900
900+150 = 1050.
Yes, it does
...
We can express this relationship by the equation:
y = mx + b
where
y = total cost
m = $6 per student
x = number of students
b = fixed costs = 150
y = 6x + 150
Step-by-step explanation:
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