Consider the following system of equations:

2 answers:

7 0

It says
which best describes the SOLUTION to the system of equations
the solution is the set of points that satisfies both equations, it is also the intersection

therfor the answer is the first option "Line y = 5x + 6 intersects line y = −x − 7."

sashaice [31]3 years ago

3 0

Answer:Line y = 5x + 6 intersects line y = −x − 7

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(6e−3f−4)⋅2=<br> otay otay

Dmitry [639]

Answer:

Step-by-step explanation:

if you need to evaluate the expression:

multiply 2 with the parenthesis

12e-6f-8

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3 years ago

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Construct the 95% confidence interval for the population mean using the appropriate distributions. a. A random sample of 50 peop

SSSSS [86.1K]

Answer: 95% confidence interval would be (26.01,29.39).

Step-by-step explanation:

Since we have given that

n = 50

Mean = 27.7

Standard deviation = 6.12

We need to construct 95% confidence interval for the population.

so, z = 1.96

So, it becomes,

$\bar{x}\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=27.7\pm 1.96\times \dfrac{6.12}{\sqrt{50}}\\\\=27.7 \pm 1.69\\\\=(27.7-1.69,27.7+1.69)\\\\=(26.01,29.39)$

Hence, 95% confidence interval would be (26.01,29.39).

4 0

4 years ago

Which two values of x are roots of the polynomial below?<br> x2-11x + 15

Alex787 [66]

The two values of roots of the polynomial $x^{2}-11 x+15$ are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

<u>Solution:</u>

Given, polynomial expression is $x^{2}-11 x+15$

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Given that $x^{2}-11 x+15$

Here a = 1, b = -11 and c = 15

On substituting the values we get,

$x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}$

$\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}$