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3 years ago

Please answer this correctly

Mathematics

2 answers:

docker41 [41]3 years ago

5 0

Answer:

1 people

Step-by-step explanation:

1 person because the plot shows only 1 9 leaf on the 10 stem.

GenaCL600 [577]3 years ago

4 0

Answer:

1 people

Step-by-step explanation:

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Ms. Bloom brought 4 packs of treats for Halloween. She gave away 2 1/9 packs of treats to her class and gave away 5/9 packs of t

Eddi Din [679]

Answer: 1 1/3 packs of treats

Step-by-step explanation:

2 1/9 + 5/9 = 2 6/9, which can be simplified to 2 2/3.

We subtract 2 2/3 from 4, giving us 1 1/3

8 0

3 years ago

What two numbers can you multiply to get 5 and add to get 8

Mashcka [7]

1 x 5 = 5 + 3 = 8
tell me if it’s not the answer your looking for

5 0

3 years ago

Find n(A) for A={0,1,2,3,...,2000}

miskamm [114]

There are 2001 items in that set.

So n(A) = 2001

We can individually count them all out, which is very slow and tedious, or we can use the formula
n-m+1

where,
m = starting value
n = ending value

In this case,
m = 0
n = 2000
So,
n-m+1 = 2000-0+1 = 2001

This formula only works if we increase the number by 1 each time (eg: 6, 7, 8, etc)

7 0

3 years ago

−5x−9y=3 plus 5x−9y=-2

Murrr4er [49]

Answer:

-18y=1

Step-by-step explanation:

Sorry if this is wrong, I was just guessing...

5 0

3 years ago

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is: