Question

15 points please help

Answer 1

Answer:

Sn = a1 (1-r^n)/ (1-r)

Step-by-step explanation:

The formula for the sum of a geometric sequence summations is given by

Sn = a1 (1-r^n)/ (1-r)

  where a1 is the first term, r is the common ratio and n is the term number we are summing up to

Answer 2

Hello from MrBillDoesMath!

Answer:

The second choice,   a1 (1-r^n)/(1-r)

Discussion:

Let

S= a1 + a1*r + a1*r^2 +......+a1* r^(n-1)                  (*)

be a geometric series with n terms

Multiply both sides by "r":

Sr = a1*r + a1*r^2 +...        + a1*r^(n-1) + a1*r^(n)    (**)            

Subtracting (*) from (**) gives

S-Sr = a1 - a1*r^(n)

       = a1 ( 1 - r^(n))

As S=Sr = S (1-r)

S (1-r) = a1 ( 1 - r^(n))

Divide both sides by (1-r)

S = a1 ( 1 - r^(n)) /(1-r)

Thank you,

MrB