Remember
(x^m)^n=x^(mn)
and
![x^{m/n}=\sqrt[n]{x^{m}}](https://tex.z-dn.net/?f=%20x%5E%7Bm%2Fn%7D%3D%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%7D%20)
(m^(2/3))^(1/2)=m^(2/6)=m^(1/3)
m^(1/3)=∛m
last one (rightmost)
Answer:
1/6 or 6/36
Step-by-step explanation:
Given the qualifications, there are six qualifying combinations out of the 36 combinations, which simplified, is 1 out of 6.
To get from C(-1, 4) to C'(-3,0), we must subtract the x value by -2. This gets us -3 (-1-2=-3). To get from 4 to 0, we must subtract the y-values by 4. This gets us a translation of 2 left and 4 down or T₋₂,₋₄
