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ivann1987 [24]
3 years ago
9

Find vertex of: y=(x-4)(x+8)

Mathematics
1 answer:
ki77a [65]3 years ago
6 0

Answer:

(-2,-36)

Step-by-step explanation:

y=(x-4)(x+8)

<u>1) Find the zeros of the parabola</u>

The zero-product property states that any value, when multiplied by 0 will equal 0. Therefore, to make y=0, either (x-4)=0 OR (x+8)=0.

Therefore, x=4 and x=-8.

<u>2) Find the x-coordinate of the vertex</u>

To do this, we take the average of our zeros.

\frac{4+(-8)}{2} \\=\frac{-4}{2} \\=-2

Therefore, the x-coordinate of the vertex is -2.

<u>3) Find the y-coordinate of the vertex</u>

Plug the x-coordinate back into the original equation

y=(-2-4)(-2+8)\\y=(-6)(6)\\y=-36

Therefore, the y-coordinate of the vertex is -36.

Therefore, the vertex of the parabola is (-2,-36).

I hope this helps!

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3 years ago
Find the area of a triangle with a base of 12 inches and a height of 9 inches.
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5 0
4 years ago
Write an equation for the line parallel to y= -2x+1 that contains (-2,5)
grin007 [14]

Answer:

y = - 2x + 1

Step-by-step explanation:

Parallels line have the same slope, when an equation is in the form y= mx + b, m is the slope. In this problem slope = - 2

Now with the slope what is missing is the y-intercept, the problem says that the line contains the point (-2, 5), replacing that point in the equation you can solve it to find the y-intercept

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3 years ago
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Answer with Step-by-step explanation:

We are given that

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Help please very much
Norma-Jean [14]

Answer:

D

Step-by-step explanation:

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3 years ago
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