We can find 3 points by plugging them in
x = -12 y = 1
x = 10 y = 0
x = 0 y = 5
I'm assuming you have to graph a line that shows the combination of earnings.
Our equation is 14.64y + 12.20x = 219.60
We'll be solving for x and y. We'll need to substitute the variables, one at a time, to 0, in order to find their intercepts.
Let's do x first.
14.64(0) + 12.20x = 219.60
12.20x = 219.60
Divide by 12.20 on both sides.
x = 18
Now let's solve for y.
14.46y + 12.20(0) = 219.60
14.46y = 219.60
Divide both sides by 14.46.
y = 15.18
That is actually a long decmal, but since we're dealing with money, we round it down to the nearest cent.
So, now we know x = 18 and y = 15.18.
Graph those on the x coordinate plane and the y coordinate plane, and make a line connecting the two. That line represents all the solutions.
Answer:
F(2, 11/2)
Step-by-step explanation:
The expression:
(x-2)² = 10(y - 3)
can be rewritten in the vertex form as follows:
(x-2)² = 10y - 30
(x-2)² + 30 = 10y
1/10(x-2)² + 3 = y
General vertex form is:
y = a(x-h)² + k
then, the vertex is locate at (h, k). In this case the vertes is (2, 3), and <em>a </em>= 1/10
The focus of a parabola is located ar F(h, k+p), where <em>p</em> = 1/(4a). Replacing into these equations:
p = 1/(4*1/10) = 5/2
F(2, 3+5/2) = F(2, 11/2)
Answer:
Step-by-step explanation:
Given a circle centred at the point P(-4,-6) and passing through the point
R(2,2).
To find its equation, we follow these steps.
Step 1: Determine its radius, r using the distance formula
For point P(-4,-6) and R(2,2)
Step 2: Determine the equation
The general form of the equation of a circle passing through point (h,k) with a radius of r is given as: 
Centre,(h,k)=P(-4,-6)
r=10
Therefore, the equation of the circle is:
