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Ira Lisetskai [31]
3 years ago
5

Find the work done in moving an object along a vector r=3i+2j-5k if the applied force is F=2i-j-k

Mathematics
2 answers:
Alex73 [517]3 years ago
8 0
The work is equivalent to the dot product of the two vectors.

W=\mathbf F\cdot\mathbf r=\langle2,-1,-1\rangle\cdot\langle3,2,-5\rangle=6-2+5=9
dexar [7]3 years ago
6 0

Answer:

W=9

Step-by-step explanation:

applying the following formula

W=r.f

here the dot indicates the dot product

then

W=(3i+2j-5k).(2i-j-k)

taking dot product

W=3.2+2.(-1)+(-5).(-1)

W=6-2+5

W=9

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