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Misha Larkins [42]
3 years ago
6

The cost of admission to the State Fair changed from $8.50 last year to $10.00 this year. Round to the nearest tenth. Show your

work. (3 points)
a.) What is the percent of change from last year to this year?
b.) Is this a percent of increase or decrease?
c.) If you have a 25% off coupon to use on the $10.00 ticket, what is the cost of your ticket?
Mathematics
1 answer:
seropon [69]3 years ago
6 0

Answer:

Percent increase is 17.6%

We still have to pay 7.50 with the coupon

Step-by-step explanation:

Percent increase = (new- original)/original *100%

                             = (10-8.5)/8.5 * 100%

                             = 1.5/8.5 * 100%

                             = 17.6470588%

Round to the nearest tenth

                                 17.6%

This is an increase since the cost went up.

If we have 25% off, we still have to pay (100%-25%) = 75%

10 *.75 = 7.50

We still have to pay 7.50 with the coupon

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What are the approximate values of the minimum and maximum points of f(x) = x5 − 10x3 + 9x on [-3,3]?
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Answer:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.

Step-by-step explanation:

Given:

f(x)=x^5-10x^3+9x; [-3,3]

Explanation:

In order to find minimum/maximum of a function, we need to find the first derivative of the function and then set it equal to 0 to get critical points.

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f'(x)=5x^4-30x^2+9

Setting derivative equal to 0, we get

5x^4-30x^2+9=0

On applying quadratic formula, we get

x=2.4, -2.4, -0.7, 0.7.

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Plugging the values x=2.4, -2.4, -0.7, 0.7, -3 and 3 in above function, we get

f(2.4)=(2.4)^5-10(2.4)^3+9(2.4)= -37.01376   : Minimum.

f(-2.4)=(-2.4)^5-10(-2.4)^3+9(-2.4)= 37.01376 : Maximum.

f(0.7)=(0.7)^5-10(0.7)^3+9(0.7) = 3.03807

f(-0.7)=(-0.7)^5-10(-0.7)^3+9(-0.7) = -3.03807

f(-3)=(-3)^5-10(-3)^3+9(-3) =0

f(3)=(3)^5-10(3)^3+9(3) =0

Therefore the approximate values of the minimum and maximum points of f(x) = x^5- 10x^3+ 9x on [-3,3] are:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.


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