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Paraphin [41]
3 years ago
10

Solve a+11/3a-5+a-21/3a-5

Mathematics
1 answer:
sineoko [7]3 years ago
8 0

Answer:   \bold{\dfrac{2(a-5)}{3a-5}}

<u>Step-by-step explanation:</u>

You can't actually "solve" this because there is no equation.  But you can simplify the expression.

\dfrac{a+11}{3a-5}+\dfrac{a-21}{3a-5}\\\\\text{Since they already have the same denominator, we can add the numerators:}\\\dfrac{a+11+a-21}{3a-5}=\dfrac{2a-10}{3a-5}=\dfrac{2(a-5)}{3a-5}\\\\\text{Since there are no common factors to cancel out, this is simplified.}

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Answer:

B

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5 0
3 years ago
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Find a quadratic function that includes the set of values below.
Mariana [72]

Answer:

f(x) = -3x^2 + 10x + 3

Step-by-step explanation:

(0,3) (2,11)(3,6)

Using the form ax^2 + bx + c = y

From the first set we know that c = 3

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and

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Use elimination to find a

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--------------subtracting eliminate b

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The equation: f(x) = -3x^2 + 10x + 3

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40 pounds of Lemon Drops are needed

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