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Paraphin [41]
4 years ago
10

Solve a+11/3a-5+a-21/3a-5

Mathematics
1 answer:
sineoko [7]4 years ago
8 0

Answer:   \bold{\dfrac{2(a-5)}{3a-5}}

<u>Step-by-step explanation:</u>

You can't actually "solve" this because there is no equation.  But you can simplify the expression.

\dfrac{a+11}{3a-5}+\dfrac{a-21}{3a-5}\\\\\text{Since they already have the same denominator, we can add the numerators:}\\\dfrac{a+11+a-21}{3a-5}=\dfrac{2a-10}{3a-5}=\dfrac{2(a-5)}{3a-5}\\\\\text{Since there are no common factors to cancel out, this is simplified.}

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Answer:

The proportion of young adults (18-25 years of age) in a certain city in the U.S. are not different from the proportion of the general population of young adults in the U.S.

Step-by-step explanation:

The hypothesis for the test can be defined as:

<em>H</em>₀: The proportion of young adults (18-25 years of age) in a certain city in the U.S. are not different from the actual proportion, i.e. <em>P</em> = <em>p</em><em>.</em>

<em>Hₐ</em>: The proportion of young adults (18-25 years of age) in a certain city in the U.S. are different from the actual proportion, i.e. <em>P</em> ≠ <em>p</em><em>.</em>

The test statistic is defined as:

z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}

Assume that the significance level of the test is, <em>α</em> = 0.05.

The decision rule is:

If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected. And vice-versa.

It is provided that the <em>p</em>-value of the test is, <em>p</em>-<em>value</em> = 0.076.

The <em>p-</em>value = 0.076 > <em>α</em> = 0.05.

Thus, the null hypothesis will not be rejected at 5% level of significance.

<u>Conclusion</u>:

The proportion of young adults (18-25 years of age) in a certain city in the U.S. are not different from the proportion of the general population of young adults in the U.S.

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