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aalyn [17]
3 years ago
6

Example 2:

Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0
Taking this example into account, we can see that setting the first value equal to 1, we obtain that F(x)=0.5x+1=4 and x=6. Using this information, we find that F(x+1)=0.5(x+1)+1=0.5(6+1)+1=4.5. It shows that when x is positive, the succussive terms are increasing.

Referring to that finding, if we set initial value less than zero, which means that we are solving 0.5x+1<0 and taking a number in the interval of the solution, which means x ∈ (- ∞, -20). Setting x=-19, we find that F(x)=0.5x+1=-19 and x=-40. In the next iteration, F(x+1)=0.5(x+1)+1=0.5(1-40)+1=-18.5. In the next iteration, F(x+2)=0.5(x+2)+1=0.5(2-40)+1=-18. By this way, we find that even if the initial value is less than zero, value of the successive iterations is increasing. 

Using the function g(x)=-x+2 and taking the initial value equal to 4, we find that g(x)=-x+2=4 and x=-2. In the next iteration, g(x+1)=-(x+1)+2=-(-2+1)+2=3. If we continue the iterations we'll see that they are decreasing.
Setting the initial value equal to 2, we find that g(x)=-x+2=2 and x=0. The next iteration is g(x+1)=-(x+1)+2=1. In this case, the interations are also decreasing. 
If we set the initial value equal to 1, we find that g(x)=-x+2=1 and x=1. In the next iteration, g(x+1)=-(x+1)+2=0 and the iterations are decreasing. 
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Step-by-step explanation:

Divide 140 by 2\frac{4}{5} to represent the amount of hours he worked.

To make dividing easier, 2\frac{4}{5} can also represent 2.8 as a decimal.

\frac{140}{2.8} =50

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