Answer:
Step-by-step explanation:
z = 119 Vertically opposite angles are equal.
5x + 41 + 119 = 180 5x + 41 and 119 are supplementary.
4x + 160 = 180 Subtract 160 from both sides
4x = 180 - 160
4x = 20 Divide by 4
x = 20/4
x = 5
This is what we know:4x^2 + 12x + c = (2x + k)^2
<span>
4x^2 + 12x + c = 4x^2 + 2kx + 2kx + k^2
c=9
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Answer:
The larger acute angle is equal to 50.8 degrees.
Step-by-step explanation:
Let's solve for both of the acute angles for the purpose of checking our work at the end with angle A being the top angle and angle B being the one on the base of the triangle (that's not the 90 degrees one). Determining whether to use sin/cos/tan comes from SOH-CAH-TOA.
A = cos^-1 (2√6/2√15)
However, you need to move the radical out of the denominator by multiplying √15 to the numerator and denominator. You should come up with (2√90)/30. So,
A = cos^-1 (2√90/30) = 50.768 degrees.
B = sin^-1 (2√90/30) = 39.231 degrees.
Now, we can check the work by adding the 2 angles to 90 and, if it comes to 180, it's right.
cos^-1 (2√90/30) + sin^-1 (2√90/30) + 90 = 180.
If you have any questions on where I got a formula or any step, feel free to ask in the comments!
<span> -2 • (5w - 3)
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45
hope this works</span>
