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Mazyrski [523]
3 years ago
15

Determine whether the following system of equations has one solution, no solution, or an infinite number of solutions. Explain y

our reasoning.
2x - 4y = 10
7x - 9y = 12
Mathematics
1 answer:
expeople1 [14]3 years ago
6 0
<span>A) 2x - 4y = 10
B) 7x - 9y = 12
Multiplying equation A by -3.5
A) -7x +14y = -35 then adding B
B) </span><span><span>7x - 9y = 12</span>
5y = -23
y = -4.6
</span>
2x -4*-4.6 = 10
2x + 18.4 = 10
2x = -8.4
x = -4.2
It has one solution (-4.2, -4.6)
 


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Step-by-step explanation:

<em>Given</em><em>,</em>

<em>-</em><em>4</em><em> </em><em>(</em><em>8</em><em> </em><em>-</em><em> </em><em>c</em><em> </em><em>)</em><em> </em><em>-</em><em> </em><em>(</em><em>3</em><em>c</em><em> </em><em>+</em><em> </em><em>7</em><em> </em><em>)</em>

<em>=</em><em> </em><em>-</em><em>4</em><em> </em><em>(</em><em> </em><em>-c </em><em>+</em><em> </em><em>8</em><em> </em><em>)</em><em> </em><em>-</em><em> </em><em>(</em><em>3</em><em>c</em><em> </em><em>+</em><em> </em><em>7</em><em> </em><em>)</em>

<em>=</em><em> </em><em>4</em><em>c</em><em> </em><em>-</em><em> </em><em>3</em><em>2</em><em> </em><em>-</em><em> </em><em>(</em><em> </em><em>3</em><em>c</em><em> </em><em>+</em><em> </em><em>7</em><em> </em><em>)</em>

<em>=</em><em> </em><em>4</em><em>c</em><em> </em><em>-</em><em> </em><em>3</em><em>2</em><em> </em><em>-</em><em> </em><em>3</em><em>c</em><em> </em><em>-</em><em> </em><em>7</em>

<em>=</em><em> </em><em>(</em><em> </em><em>4</em><em> </em><em>-</em><em> </em><em>3</em><em> </em><em>)</em><em>c </em><em>+</em><em> </em><em>(</em><em> </em><em>-</em><em>3</em><em>2</em><em> </em><em>-</em><em> </em><em>7</em><em> </em><em>)</em>

<em>=</em><em> </em><em>c </em><em>+</em><em> </em><em>(</em><em> </em><em>-</em><em>3</em><em>2</em><em> </em><em>-</em><em> </em><em>7</em><em>)</em>

<em>=</em><em> </em><em><u>C </u></em><em><u>-</u></em><em><u> </u></em><em><u>3</u></em><em><u>9</u></em>

<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps </u></em><em><u>you </u></em><em><u>dear!</u></em><em><u> </u></em><em><u>take </u></em><em><u>care!</u></em>

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ella [17]
<span>the notebook
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We have a mixed operation with numbers . Each number is a whole and fractions . Then we subtract the total from the whole and fractions of fractions
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9  \frac{1}{5}  - 3  \frac{2}{3} = \\  \\  3 + 6  \frac{1}{5} - 3 -  \frac{2}{3} = \\  \\  6  \frac{1}{5}  -  \frac{2}{3}  =

<span>by subtracting fractions must have the same value in the denominator .
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6  \frac{1*3}{5*3}  -  \frac{2*5}{3*5}  = \\  \\ 6  \frac{3}{15}  -  \frac{10}{15} =

3/15 < 10/15 <span>We have to take the total 1 to subtract it was possible
</span>
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