3 years ago

Solve ( x− 4)^2 = 9.

Mathematics

2 answers:

Marysya12 [62]3 years ago

8 0

Answer:

= 7

Step-by-step explanation:

IgorC [24]3 years ago

5 0

Answer:

x= 7, 1

Step-by-step explanation:

Take the root of both sides and solve.

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X2 + 5x - 50 A) (x + 25)(x - 2) B) (x - 5)(x + 10) C) (x - 10)(x + 5) D) (x + 2)(x - 25)

olga2289 [7]

Answer:

The correct answer is B) (x - 5)(x + 10)

Step-by-step explanation:

The constants at the end of the parenthesis need to add to the middle term

10 + -5 = 5

And they need to multiply to the end term

-5 * 10 = -50

This makes it the correct choice.

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scoundrel [369]

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rusak2 [61]

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3 years ago

Read 2 more answers

Perform the indicated operation. 15b/4 * 8/9a^2b^2

Sergio [31]

Answer:

The simplified expression is $\frac{10}{3 a^2 b}$

Step-by-step explanation:

The given expression is:

$\frac{15b}{4} * \frac{8}{9a^2 b^2}$

Multiply the items in the numerator together ( 15b * 8 = 120 b). Also multiply the items in the denominator together ( 4 * 9a²b² = 36a²b²). The expression thus becomes:

$= \frac{120b}{36 a^2 b^2} \\\\$

Divide both the numerator and the denominator by 12b:

$= \frac{120b /12b}{36 a^2 b^2/12b}$

The expression finally becomes:

$= \frac{10}{3 a^2 b}$

7 0

3 years ago

What is the equation of the trend line?<br> Enter your answers in the boxes.<br><br> K = _J +_

MrRissso [65]

The y-intercept of the trend line is (0,28). The slope of this line is
28-0
m = --------- = 2
14-0

Thus, the equation of the trend line, in variables K and J, is

K = 2J + 28

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3 years ago