Ok so let's start with what we know- the shortest piece is 8 inches so there's one length... then the middle piece is 6 inches longer than the shortest (6+ 8) so the middle piece would be 14 inches long. To find the last piece we can add up the other two pieces we know (14+8) which would be 22 and subtract that from how long the whole sandwich is (59-22) which would be 37 inches long. So in the end he shortest piece would be 8 inches, the middle 14 inches and the longest 37 inches.
Answer:
468
Step-by-step explanation:
=13[42-6]
=13 (36)
=13×36
=468
<h2>
Hello!</h2>
The answer is: The first graphic representation.
<h2>
Why?</h2>
We are given a quadratic equation, meaning that it could be two possible solutions for the exercise, however, we are talking about time, so we have to consider only the obtained positive values.
Let's make the equation equal to 0 in order to find the values of "t"
So, discarding the negative value, we can use the possitive value to find the correct graphic representation.
To find the correct graphic representation we must take into consideration the following:
- We must remember that the sign of the coefficient of the quadratic term (t^2) will define if the parabola opens downward or upward.
From the given quadratic (or parabola) equation we have:
So, since the coefficient of the quadratic term is negative, the parabola opens downward.
- Since we are looking for a graphic that represents the change in height over time, we need to look for a graphic that shows only positive values for the x-axis (time)
- We are looking for a parabola which y-axis intercept is equal to 150.
Therefore, the graphic representation of the quadratic function that models a ball's height over time is the first graphic representation.
Have a nice day!
Given
P(1,-3); P'(-3,1)
Q(3,-2);Q'(-2,3)
R(3,-3);R'(-3,3)
S(2,-4);S'(-4,2)
By observing the relationship between P and P', Q and Q',.... we note that
(x,y)->(y,x) which corresponds to a single reflection about the line y=x.
Alternatively, the same result may be obtained by first reflecting about the x-axis, then a positive (clockwise) rotation of 90 degrees, as follows:
Sx(x,y)->(x,-y) [ reflection about x-axis ]
R90(x,y)->(-y,x) [ positive rotation of 90 degrees ]
combined or composite transformation
R90. Sx (x,y)-> R90(x,-y) -> (y,x)
Similarly similar composite transformation may be obtained by a reflection about the y-axis, followed by a rotation of -90 (or 270) degrees, as follows:
Sy(x,y)->(-x,y)
R270(x,y)->(y,-x)
=>
R270.Sy(x,y)->R270(-x,y)->(y,x)
So in summary, three ways have been presented to make the required transformation, two of which are composite transformations (sequence).
