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motikmotik
4 years ago
13

Find the coordinates of a second point on the graph of a function f if the given point is on the graph and the function is (a) e

ven and (b) odd.?
(4,9)
Mathematics
1 answer:
hoa [83]4 years ago
8 0
<span>For odd function:
 f(x) = - f(-x). 

For function is even,
 f(x) = f(-x). 

using the above laws 
for odd function:
 f(4) = 9 = - f(-4)
f(-4) = -9
so the second  point is (-4,-9) 

for even function: f(4) = 9 = f(-4)
 so the second point is (-4,9)</span>
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rows of chairs are set out for a wedding. there are 6 chairs in the first row, 14 chairs in the second row, and 22 chairs in the
fomenos
This is just a simple multi-step math problem. The first step to finding the answer is to find out the pattern of the chairs. So, we would take two of the numbers, 14 and 6, and subtract 14 from 6.

14 - 6 = 8

So now we know that the difference between the first to rows is 8 chairs. To double check this pattern you would simply subtract 14 from 22.

22 - 14 = 8

Okay, so now we are sure that the pattern is by simply adding 8 to the number of chairs in the row before. Now that we have a pattern all set, there are two different ways to solve this problem, yet I am going to use the longer method. You would simply start from 6 and keep adding on 8's until you would reach the 7th row like so:

6 + 8 = 14
14 + 8 = 22
22 + 8 = 30
30 + 8 = 38
38 + 8 = 46
46 + 8 = 54

So as you can see, the total number of chairs would be 54. This may take a little longer to do, as I happened to use the longer method for this problem. Yet I hope this still helped :)!
3 0
3 years ago
What is the area of this parallelogram PLEASE HELP QUICKLY!!!20 points!!!
olga nikolaevna [1]

Answer:

72

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Brenda cuts her grass every 15 days and trims her shrubs every 24 days. if brenda cut her grass and trimmed her shrubs on june​
wariber [46]
To get the number of days that will pass before Brenda cuts her grass and shrubs on the same day will be found using least common multiple:
15=3×5
24=3×8
thus the LCM (24,15)=120 days
She will cut the grass again after 120 days
7 0
3 years ago
Help please I’m not good at rational functions.
GuDViN [60]

Answer:

See below.

Step-by-step explanation:

\frac{6z^2-12z}{4z^2-16z+16} +\frac{3z}{z^2-z-2} \\\\

First, factor the numerators and the denominators:

=\frac{6z(z-2)}{4(z^2-4x+4)}+\frac{3z}{z^2-z-2}\\=\frac{6z(z-2)}{4(z-2)^2}+\frac{3z}{(z-2)(z+1)}\\=\frac{3z}{2(z-2)}+\frac{3z}{(z-2)(z+1)}

Now, make the two denominators equivalent. To do this, we can multiply the first term by (z+1) and multiply the second term by 2. This will give us:

(\frac{z+1}{z+1} )(\frac{3z}{2(z-2)})+(\frac{2}{2})(\frac{3z}{(z-2)(z+1)})\\=\frac{3z(z+1)}{2(z-2)(z+1)}+\frac{6z}{2(z-2)(z+1)}  \\

Now, combine them since they have a common denominator:

=\frac{3z^2+3z+6z}{2(z-2)(z+1)}\\ =\frac{3z^2+9z}{2(z-2)(z+1)} \\=\frac{3z(z+3)}{2(z-2)(z+1)}

This cannot be simplified further.

7 0
3 years ago
In analyzing hits by certain bombs in a​ war, an area was partitioned into 553 ​regions, each with an area of 0.95 km2. A total
Leto [7]

Answer:

Probability of having two hits in the same region = 0.178

mu: average number of hits per region

x: number of hits

e: mathematical constant approximately equal to 2.71828.

Step-by-step explanation:

We can describe the probability of k events with the Poisson distribution, expressed as:

P(x=k)=\frac{\mu^ke^{-\mu}}{k!}

Being μ the expected rate of events.

If 535 bombs hit 553 regions, the expected rate of bombs per region (the events for this question) is:

\mu=\frac{\#bombs}{\#regions} =\frac{535}{553}= 0.9674

For a region to being hit by two bombs, it has a probability of:

P(x=2)=\frac{\mu^2e^{-\mu}}{2!}=\frac{0.9674^2e^{-0.9674}}{2!}=\frac{0.9359*0.38}{2}=0.178

4 0
3 years ago
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