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lbvjy [14]
3 years ago
6

rows of chairs are set out for a wedding. there are 6 chairs in the first row, 14 chairs in the second row, and 22 chairs in the

third row. the rows continue in the same pattern for a total of seven rows. How many chairs are set out for the wedding guests
Mathematics
1 answer:
fomenos3 years ago
3 0
This is just a simple multi-step math problem. The first step to finding the answer is to find out the pattern of the chairs. So, we would take two of the numbers, 14 and 6, and subtract 14 from 6.

14 - 6 = 8

So now we know that the difference between the first to rows is 8 chairs. To double check this pattern you would simply subtract 14 from 22.

22 - 14 = 8

Okay, so now we are sure that the pattern is by simply adding 8 to the number of chairs in the row before. Now that we have a pattern all set, there are two different ways to solve this problem, yet I am going to use the longer method. You would simply start from 6 and keep adding on 8's until you would reach the 7th row like so:

6 + 8 = 14
14 + 8 = 22
22 + 8 = 30
30 + 8 = 38
38 + 8 = 46
46 + 8 = 54

So as you can see, the total number of chairs would be 54. This may take a little longer to do, as I happened to use the longer method for this problem. Yet I hope this still helped :)!
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Please help!!!!! it's a word problem and I don't understand how to do it at all
andre [41]
7We can see that line NM = JK so NM also equals 10.
We know NL = 23 and NM = 10 therefore, ML = NL -NM  ML = 23 -13
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