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mash [69]
3 years ago
11

The area of a rectangular wall of a barn is 32 square feet. It’s length is 4 feet longer than the width. Find the length and wid

th of the wall of the barn
Mathematics
1 answer:
Gnom [1K]3 years ago
6 0

Answer:

Step-by-step explanation:

Givens

Area = L * w

w = x

l = x  + 4

Area = 32

Solution

32 = x(x + 4)

32 = x^2 + 4x

x^2 + 4x - 32

(x + 8)(x - 4)

Only x - 4 is going to make any sense

x - 4 = 0

x = 4

The width is 4

The length is 4 + 4 = 8

4*8 = 32 which is the area.

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Answer:

y  = -6(x - \frac{1}{2})^2 -\frac{7}{2}

Step-by-step explanation:

Given:

y = -6x^2 + 3x + 2

Required

Rewrite in vertex form

The vertex form of an equation is in form of: y = a(x - h)^2+ k

Solving: y = -6x^2 + 3x + 2

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y - 2 = -6x^2 + 3x + 2 - 2

y - 2 = -6x^2 + 3x

Factorize expression on the right hand side by dividing through by the coefficient of x²

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y - 2 = -6(x^2 - \frac{3x}{6})

y - 2 = -6(x^2 - \frac{x}{2})

Get a perfect square of coefficient of x; then add to both sides

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<em>Rough work</em>

The coefficient of x is \frac{-1}{2}

It's square is (\frac{-1}{2})^2 = \frac{1}{4}

Adding inside the bracket of -6(x^2 - \frac{x}{2}) to give: -6(x^2 - \frac{x}{2} + \frac{1}{4})

To balance the equation, the same expression must be added to the other side of the equation;

Equivalent expression is: -6(\frac{1}{4})

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The expression becomes

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y - 2 -\frac{6}{4}= -6(x^2 - \frac{x}{2} + \frac{1}{4})

y - 2 -\frac{3}{2}= -6(x^2 - \frac{x}{2} + \frac{1}{4})

Factorize the expression on the right hand side

y - 2 -\frac{3}{2}= -6(x - \frac{1}{2})^2

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Make y the subject of formula

y  = -6(x - \frac{1}{2})^2 -\frac{7}{2}

<em>Solved</em>

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