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4 years ago

in an Arthemitic progression, if the common difference (d= -4) and the seventh term is 4 then find the first 3 terms

Mathematics

1 answer:

vekshin14 years ago

7 0

Answer:

28, 24, 20

Step-by-step explanation:

The n th term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

here d = - 4 and a₇ = 4, hence

a₁ + (6 × - 4) = 4

a₁ - 24 = 4 ( add 24 to both sides ), hence

a₁ = 28

a₂ = 28 - 4 = 24

a₃ = 24 - 4 = 20

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in an Arthemitic progression, if the common difference (d= -4) and the seventh term is 4 then find the first 3 terms​

in an Arthemitic progression, if the common difference (d= -4) and the seventh term is 4 then find the first 3 terms