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liberstina [14]
4 years ago
12

Use the function rule to complete the table -10x+y=4

Mathematics
2 answers:
Bingel [31]4 years ago
8 0
Just plug the numbers in the table into your formula and solve for X
Blizzard [7]4 years ago
5 0
-10x+y=4

u just need to plug in values of x in function to get y values
x=-2

-10(-2)+y=4
20+y=4
y=-16

-10x+y=4
x=-1
-10(-1)+y=4
10+y=4
y=-6

-10x+y=4
 at x=0
-10(0)+y=4
y=4
u are getting y values according to x values

y=-16 at x=-2
y=-6 at x= -1
y=4 at x=0

next u can find




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Simplify the expression by combining like terms.<br><br> 3.6x+5.9−2.2−1.7x
makvit [3.9K]

Answer:

1.9x+3.7

Step-by-step explanation:

Subtract 3.6x-1.7x

and 5.9-2.2    

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Q4<br> Help pleaseeeeeeee
emmasim [6.3K]

a. The general equation for a circle centered at (a,b) with radius r is

(x-a)^2+(y-b)^2=r^2

The described circle has equation

(x+3)^2+(y+2)^2=r^2

We know the circle passes through the origin. This means that the equation above holds for x=0 and y=0. The distance between any point on the circle and its center is the radius, so we can use this fact to determine r:

(0+3)^2+(0+2)^2=r^2\implies 9+4=13=r^2\implies r=\sqrt{13}

So the circle's equation is

(x+3)^2+(y+2)^2=(\sqrt{13})^2=13

b. If the distance between point B and the center is less than \sqrt{13}, then B lies inside the circle. If the distance is greater than \sqrt{13}, it falls outside the circle. Otherwise, if the distance is exactly \sqrt{13}, then B lies on the circle.

The distance from B to the center is

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5 0
3 years ago
Can you help me with my work
coldgirl [10]

Answer:

1. 9 or -9

2. 3.6  or  -3.6

3. 12 and -12

4. The quadratic function has no real roots.

Step-by-step explanation:

1. Solve x² -81 = 0

x² -81 = 0

x² = 81

x = ±√81

x = 9      or   x = -9


2. solve 2x² - 26 = 0

 2x² - 26 = 0

2x² = 26

x² = 13

x = ±√13

∴ x = 3.6      or    x = -3.6


3. f(x) = x² - 144

let f(x) = 0

x² - 144 = 0

x² = 144

x = ±√144

x = 12   and  x = -12


4. f(x) = x² + 25

let f(x) = 0

x² + 25 = 0

x² = -25

x = ±√(-25)

There is no square root of a negative number. Its square is not a real number.

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3 years ago
These angles can be proven congruent by:
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Answer:

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