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alex41 [277]
3 years ago
9

If sin A = 3/5 and the cosA =4/5 then what is tan A

Mathematics
2 answers:
Ratling [72]3 years ago
5 0

Answer:

Tan A = 3/4

Step-by-step explanation:

sin A = y/r

Cos A = x/r

Tan A = y/x

xxTIMURxx [149]3 years ago
4 0

Answer:

3/4

Step-by-step explanation:

sin A = 3/5

cosA =4/5

We know that tan A = sin A / cos A

                                   = 3/5  /   4/5

                                    = 3/5 * 5/4

                                    = 3/4

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In a survey of consumers aged 12 and​ older, respondents were asked how many cell phones were in use by the household.​ (No two
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Answer:

The probability that​ his/her household has four or more cell phones in use is 0.122 or 12.2%.

Step-by-step explanation:

<u>The complete question is</u>: In a survey of consumers aged 12 and​ older, respondents were asked how many cell phones were in use by the household.​ (No two respondents were from the same​ household.) Among the​ respondents, 215 answered​ "none", 280 said​ "one", 362 said​ "two", 149 said​ "three," and 140 responded with four or more. A survey respondent is selected at random. Find the probability that​ his/her household has four or more cell phones in use. Is it unlikely for a household to have four or more cell phones in​ use? Consider an event to be unlikely if its probability is less than or equal to 0.05.

We are given that among the​ respondents, 215 answered​ "none", 280 said​ "one", 362 said​ "two", 149 said​ "three," and 140 responded with four or more.

A survey respondent is selected at random.

As we know that the probability of any event is calculated as;

                Probability = \frac{\text{Favorable number of outcomes}}{\text{Total number of outcomes}}

Here, we have to find the probability that​ his/her household has four or more cell phones in use;

Number of respondent having four or more cell phones in use = 140

Total number of respondents asked = 215 + 280 + 362 + 149 + 140 = 1146

<u>So, the required probability</u> = \frac{140}{1146}

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No, it is not unlikely for a household to have four or more cell phones in​ use because the probability is not less than or equal to 0.05 but in actual it is greater than 0.05.

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