1.2.and 3 please due in q hour
1 answer:
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<h3>Answer: D) 5</h3>
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Explanation:
If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first
x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator
So,
Allowing us to say,
Answer:
r(t) and s(t) are parallel.
Step-by-step explanation:
Given that :
the lines represented by the vector equations are:
r(t)=⟨1−t,3+2t,−3t⟩
s(t)=⟨2t,−3−4t,3+6t⟩
The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.
NOTE:
Two lines will be parallel if
here;
Thus;
∴
Hence, we can conclude that r(t) and s(t) are parallel.
Answer:
Step-by-step explanation:
Isolate the parts of the equation with the x variable
When you divide or multiply by a negative number in inequalities, you must flip the sign of the inequality.