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3 years ago

Identify the equation that describes the line in slope-intercept form.

Mathematics

2 answers:

slega [8]3 years ago

8 0

Answer y-2x+5 or it will be y=-2x+11

Step-by-step explanation:

pshichka [43]3 years ago

7 0

Answer:

I have

Step-by-step explanation:

No idea i just need points sorry wyatt

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A random sample of size 15 is selected from a normal population. The population standard deviation is unknown. Assume the null h

taurus [48]

Answer:

Interval for t statistic = (-1.345, 1.345)

Step-by-step explanation:

given that a random sample of size 15 is selected from a normal population. The population standard deviation is unknown.

Since population std deviation is unknown and also sample size <30, we have to use t test only for testing of hypothesis

Given it is a two tailed test at 10% significance level.

Degree of freedom = 15-1 =14

t critical value for df 14 two tailed is

1.345

Hence our test statistic should lie between

(-1.345, 1.345)

Then null hypothesis is accepted

Other wise it is rejected.

4 0

3 years ago

In quadratic drag problem, the deceleration is proportional to the square of velocity

Mars2501 [29]

Part A

Given that $a= \frac{dv}{dt} =-kv^2$

Then,

$\int dv= -kv^2\int dt \\ \\ \Rightarrow v(t)=-kv^2t+c$

For $v(0)=v_0$ , then

$v(0)=-kv^2(0)+c=v_0 \\ \\ \Rightarrow c=v_0$

Thus, $v(t)=-kv(t)^2t+v_0$

For $v(t)= \frac{1}{2} v_0$ , we have

$\frac{1}{2} v_0=-k\left( \frac{1}{2} v_0\right)^2t+v_0 \\ \\ \Rightarrow \frac{1}{4} kv_0^2t=v_0- \frac{1}{2} v_0= \frac{1}{2} v_0 \\ \\ \Rightarrow kv_0t=2 \\ \\ \Rightarrow t= \frac{2}{kv_0}$

Part B

Recall that from part A,

$v(t)= \frac{dx}{dt} =-kv^2t+v_0 \\ \\ \Rightarrow dx=-kv^2tdt+v_0dt \\ \\ \Rightarrow\int dx=-kv^2\int tdt+v_0\int dt+a \\ \\ \Rightarrow x=- \frac{1}{2} kv^2t^2+v_0t+a$

Now, at initial position, t = 0 and $v=v_0$ , thus we have

$x=a$

and when the velocity drops to half its value, $v= \frac{1}{2} v_0$ and $t= \frac{2}{kv_0}$

Thus,

$x=- \frac{1}{2} k\left( \frac{1}{2} v_0\right)^2\left( \frac{2}{kv_0} \right)^2+v_0\left( \frac{2}{kv_0} \right)+a \\ \\ =- \frac{1}{2k} + \frac{2}{k} +a$

Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by

$- \frac{1}{2k} + \frac{2}{k} +a-a \\ \\ = \frac{2}{k} - \frac{1}{2k} = \frac{3}{2k}$

7 0

3 years ago

Able, Ben and Cal each played a game able’s score was six times ben’s score, Cale score was a hird time of Able’s score write do

Deffense [45]

Answer:

6:1:2

Step-by-step explanation:

Let a = Able's score, b = Ben's score, and c = Cal's score.

Since

Able's score was 6 times Ben's score, that means a = 6b.

Cal's score was a third of Able's score, so that means c = a/3. And since a = 6b, that means c = 6b / 3 = 2b.

Thus, the ratio of Able's score to Ben's score to Cal's score, a:b:c, is 6:1:2, because c is twice as much as b and a is 6 times as much as b.

7 0

3 years ago

If bc+ad=b solve for a

stiv31 [10]

Answer:

bc+ad=b

or,ad=b-bc

or,a=(b-bc)/d

7 0

3 years ago

Read 2 more answers

What is the fraction for 5copies of 1/5

Sergeeva-Olga [200]

Answer:

5 x 1/5 = 1 whole

The key word "of" means multiplication.

5 0

2 years ago