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3 years ago

State the amplitude, period, phase shift, and vertical shift of the function h(t)= cos (t+1)

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

5 0

Answer:

Option b.

Step-by-step explanation:

We can easily solve this problem by using a graphing calculator or plotting tool.

The function is

h(t) = cos (t +1)

Please, see attached picture below.

By looking at the picture, we can tell that the amplitude is equal to 1

The function has a period of T = 2π

We can see there is no vertical shift.

It has a phase shift of +1. (Which moves the graph to the left)

Answer:

Option b.

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Expert Answer

Step-by-step explanation:

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3 years ago

Which expression is equivalent to (4x^(3)y^(5))(3x^(5)y)^(2)

marshall27 [118]

Answer:

$(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7$

Step-by-step explanation:

Given

$(4x^3y^5)(3x^5y)^2$

Required

The equivalent expression

We have:

$(4x^3y^5)(3x^5y)^2$

Expand

$(4x^3y^5)(3x^5y)^2 = 4x^3y^5*9x^{10}y^2$

Further expand

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