The smallest of the three consecutive integers is 24.
Let the 3 consecutive integers be;
x, y and z
Thus;
y = x + 1
z = x + 2
Now, we are told that their sum is equal to 4 times the largest number minus 29. Thus;
x + x + 1 + x + 2 = 4(x + 2) - 29
3x + 3 = 4x + 8 - 29
4x - 3x = 3 + 21
x = 24
Thus, we can conclude that the smallest of the three consecutive integers is 24.
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Answer:
Step-by-step explanation:
11:35 or b
12
48/4=12 x=12