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2 years ago

The sum of three consecutive numbers is equal to 4 times the largest number minus 29. What is the smallest of the three numbers?

Mathematics

1 answer:

gulaghasi [49]2 years ago

5 0

The smallest of the three consecutive integers is 24.

<h3>How to solve algebraic word problems?</h3>

Let the 3 consecutive integers be;

x, y and z

Thus;

y = x + 1

z = x + 2

Now, we are told that their sum is equal to 4 times the largest number minus 29. Thus;

x + x + 1 + x + 2 = 4(x + 2) - 29

3x + 3 = 4x + 8 - 29

4x - 3x = 3 + 21

x = 24

Thus, we can conclude that the smallest of the three consecutive integers is 24.

Read more about algebra word problems at; brainly.com/question/13818690

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your question is incomplete, here you can find the complete question below:

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the varying radian measure of the angle.

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b. if the terminal ray of the angle passes through the point(1.49,3.82), whta is the slope of the terminal ray of the angle?

c. if the terminal ray of the angle passes through the point(1.1,3.95), what is the slope of the terminal ray of the angle?

Answer:

a. 1.45

b. 2.56

c. 3.59

Step-by-step explanation:

As we know that formula to find the slope is change in y-coordinates divided by change in x-coordinates.

$slope=\frac{chnage\ in\ y}{chnage\ in\ x}=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

It is given that initial point is (x1,y1)=(0,0)

Part(a)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(3.38,2.32)

so the slope of the terminal ray is

$slope=\frac{3.38-0}{2.32-0}=\frac{3.38}{2.32}= 1.45$

Part(b)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.49,3.82)

so the slope of the terminal ray is

$slope=\frac{3.82-0}{1.49-0}=\frac{3.82}{1.49}=2.56$

Part(c)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.1,3.95)

so the slope of the terminal ray is

$slpoe=\frac{3.95-0}{1.1-0}=\frac{3.95}{1.1}= 3.59$

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