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3 years ago

If ∠G ≅ ∠H, then ∠H ≅ ∠G. name the property

Mathematics

1 answer:

USPshnik [31]3 years ago

7 0

Answer:

Property of Symmetry

Step-by-step explanation:

The symmetric property of equality tells us that both sides of an equal sign are equal no matter which side of the equal sign they are on. Remember it states that if x = y, then y = x.

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Answer:

I would say the answer is c

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3 years ago

What is the value of ( 0.4) ^3

cestrela7 [59]

Answer:

0.064

Step-by-step explanation:

( 0.4) ^3

Solution :

( 0.4) ^3

= 0.4 x 0.4 x 0.4

= 0.064

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3 years ago

Estimate the product of 73 and 28

andreyandreev [35.5K]

Round the numbers to 70 and 30, then multiply them together to get the product of 2100

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3 years ago

Read 2 more answers

Plz help<br>urgent !!!!<br>will give the brainliest !!

Mkey [24]

Answer:

$X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}$

Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

If we have to isolate $X$ here, then we would have to take the inverse of the following matrix ...

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}$ ... so that it should be as follows ... $\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}$

Therefore, we can conclude that the equation as to solve for " $X$ " will be the following,

$X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ - First find the 2 x 2 matrix inverse of the first portion,

$\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}$ = $\frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}$ = $\frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix}$ = $\begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}$

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

$X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ ,

$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...

$\begin{bmatrix}1&3\\ 2&4\end{bmatrix}$ ... which is our solution.

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3 years ago

If a1=47 and d=-5 find a12

Simora [160]

An = a1 + (n-1) * d
a12 = 47 + (12 - 1) * -5
a12 = 47 + 11 * -5
a12 = 47 - 55
a12 = - 8 <==

8 0

3 years ago