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Mumz [18]
2 years ago
10

Please answer!

Mathematics
1 answer:
Xelga [282]2 years ago
8 0

Amswer

it is b Step-by-step explanation:

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What is the area of this figure?
Elanso [62]
First of all we can draw a parallel line to divide the figure into a triangle and a rectangle as shown in the figure. To find the area of our rectangle, remember that the area of a rectangle is length times width, so A_{r} =lw. Since we know for our figure that the length and width of our rectangle are 13cm and 6cm respectively, lets replace those values in our formula to get its area:
A _{r} =(13cm)(6cm)
A=78cm^{2}
Similarly, the area of a triangle is one half times base times height, so At=( \frac{1}{2})bh. Since we know that our base is 8cm and our height 6cm, lets replace those values in our equation to find the area of our triangle:
A_{t} =( \frac{1}{2})(8cm)(6cm)
A_{t} =24cm^{2}

Now the only thing left is add our areas:
 A_{total} =78cm^{2}+24cm^{2}  =102cm^{2}

We can conclude that the correct answer is <span>A. 102</span>

4 0
3 years ago
I WILL GIVE BRAINLIEST!!!! Solve the problems. Write the complete proof in your paper homework and for online (only) respond to
Komok [63]

Answer:

Step-by-step explanation:

we need the problems to solve so erm yeah can you like tell me them please but to solve triangles you have to find the angles. hope i helped a bit

7 0
3 years ago
Read 2 more answers
Please help! And thank you for your time.
Ulleksa [173]
B. You can get this by factoring the bottom of the first expression and then cancelling the terms. Then multiply by the inverse of the second.
6 0
3 years ago
In circle P what is the measure(in degrees) of arc ADB?
ruslelena [56]

Answer:

A: 270 ,':)

Step-by-step explanation:

8 0
3 years ago
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Solve (9^5/9^3) Please show steps along with it
Luda [366]
9^5 is 9*9*9*9*9 you * 9 by how ever many little number there is so you get 59049
and with 9^3 its 9*9*9 729
its NEVER 9*3 or 9*5 you have to times the same number () time the littler number it telling you how many time to do so
3 0
3 years ago
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