Answer:
![W=2452.5 J](https://tex.z-dn.net/?f=W%3D2452.5%20J)
Step-by-step explanation:
The work is define as the integral of the force times distance. So we have:
![W=\int^{a}_{b}Fxdx](https://tex.z-dn.net/?f=W%3D%5Cint%5E%7Ba%7D_%7Bb%7DFxdx)
Now, we can write the force in terms of density.
![F=m*g=\rho Vg](https://tex.z-dn.net/?f=F%3Dm%2Ag%3D%5Crho%20Vg%20)
V is the volume (V=2*1*1=2 m³)
So the work will be:
![W=\int^{0.5}_{0} 2*1000*9.81*xdx=\int^{0.5}_{0} 2*1000*9.81*xdx=\int^{0.5}_{0}19620xdx=19620(\frac{x^{2}}{2})|^{0.5}_{0}](https://tex.z-dn.net/?f=W%3D%5Cint%5E%7B0.5%7D_%7B0%7D%202%2A1000%2A9.81%2Axdx%3D%5Cint%5E%7B0.5%7D_%7B0%7D%202%2A1000%2A9.81%2Axdx%3D%5Cint%5E%7B0.5%7D_%7B0%7D19620xdx%3D19620%28%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%29%7C%5E%7B0.5%7D_%7B0%7D)
The limit of integration is between 0 and 0.5 because we want to pump half of the water out of the aquarium.
![W=19620(\frac{x^{2}}{2})|^{0.5}_{0}=19620(\frac{0.5^{2}}{2})](https://tex.z-dn.net/?f=W%3D19620%28%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%29%7C%5E%7B0.5%7D_%7B0%7D%3D19620%28%5Cfrac%7B0.5%5E%7B2%7D%7D%7B2%7D%29)
![W=2452.5 J](https://tex.z-dn.net/?f=W%3D2452.5%20J)
I hope it helps you!
Answer:
60 minutes is 20% of 300 minutes
Step-by-step explanation:
let x be the number of total minutes
60 = 20% of x
20% = 1/5
60 = 1/5x
multiply both sides by 5
300 = x
x = 300 minutes
Answer:
yes
Step-by-step explanation:
Answer:
-11/4
Step-by-step explanation:
(-8 - 3)/[3-(-1)]= -11/4
4x-5y=3
4x-5(10)=3
4x-50=3
+50 +50
4x=53
/4 /4
x=53/4