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3 years ago

Marissa got an 85% on her math quiz. If she got 34 questions correct, know how many questions were on the quiz.

Mathematics

2 answers:

ikadub [295]3 years ago

8 0

Answer: 40

Reasoning: 34/.85= 40

40x.85=34

worty [1.4K]3 years ago

6 0

Let q represent the total number of questions on the quiz. Then 0.85q = 34, and q = 34/0.85 = 40. There were 40 questions on the quiz.

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a crowbar of 2cm is used to lift an object if 800N. if the effort arm is 260cm. calculate the effort applied.

Gelneren [198K]

Answer:

solution:Here

Given,

Load=800 N

Load distance=2cm

Effort distance=260cm

Effort applied=?

We know that,

Load × Load distance = Effort × Effort distance

or, 800×2 = e × 260

or,1600 = 260e

or,e = 1600/260

Thus, e = 6.15 N

Hence, The effort applied = 6.15 N

Hope this answer helped you..

Please mark me as brainliest

8 0

9 months ago

HELPPP PLSS WILL GIVE BRAINLIST MMM

Liula [17]

Answer:

29.5m

Step-by-step explanation:

5m×5.9m

=29.5m

8 0

3 years ago

Lucy has one and one fourth cup of sugar in a cookie recipe calls for 2/3 cup of sugar how many cups of sugar will she have left

cluponka [151]

Answer:

$\frac{7}{12}$

Step-by-step explanation:

$1 \frac{1}{4} - \frac{2}{3} = \frac{5}{4} - \frac{2}{3} = \frac{15 - 8}{12} = \frac{7}{12}$

5 0

3 years ago

Find all geometric sequences such that the sum of the first two terms is 24 and the sum of the first three terms is 26.

Serga [27]

Answer:

<h3>The nth term Tn = -8(-1/4)^(n-1) or Tn = 6(1/3)^(n-1) can be used to find all geometric sequences</h3>

Step-by-step explanation:

Let the first three terms be a/r, a, ar... where a is the first term and r is the common ratio of the geometric sequence.

If the sum of the first two term is 24, then a/r + a = 24...(1)

and the sum of the first three terms is 26.. then a/r+a+ar = 26...(2)

Substtituting equation 1 into 2 we have;

24+ar = 26

ar = 2

a = 2/r ...(3)

Substituting a = 2/r into equation 1 will give;

(2/r))/r+2/r = 24

2/r²+2/r = 24

(2+2r)/r² = 24

2+2r = 24r²

1+r = 12r²

12r²-r-1 = 0

12r²-4r+3r -1 = 0

4r(3r-1)+1(3r-1) = 0

(4r+1)(3r-1) = 0

r = -1/4 0r 1/3

Since a= 2/r then a = 2/(-1/4)or a = 2/(1/3)

a = -8 or 6

All the geometric sequence can be found by simply knowing the formula for heir nth term. nth term of a geometric sequence is expressed as

if r = -1/4 and a = -8

Tn = -8(-1/4)^(n-1)

if r = 1/3 and a = 6

Tn = 6(1/3)^(n-1)

The nth term of the sequence above can be used to find all the geometric sequence where n is the number of terms

6 0

3 years ago

A trough is 12 ft long and its ends have the shape of isosceles triangles that are 3 ft across at the top and have a height of 1

V125BC [204]

Answer:

$\frac{dh}{dt}=0.5ft$

Step-by-step explanation:

From the question we are told that:

Length $l=12$

Top length $l_t=3ft$

Height $h=1ft$

Rate $R=14 ft3/min$

Water rise $w=4$

Generally the equation for Velocity is mathematically given by

$V=frac{1}{2}wh'(l)\\\\V=frac{1}{2}wh'(12)$

$V=18h'^2$

Therefore

$R=18(2h)(\frac{dh}{dt})$

Where

$h=\frac{3}{4}$

Therefore

$\frac{dh}{dt}=\frac{R}{18(2h)}$

$\frac{dh}{dt}=\frac{14}{18(2.3/4)}$

$\frac{dh}{dt}=0.5ft$

8 0

3 years ago