The problem for my last question. Plz answer!
1 answer:
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Answer:
$15.63 ≤ x ≤ $54.365
Step-by-step explanation:
Profit of the phone company is modeled by the equation,
p(x) = -50x² + 3500x - 2500
For the profit of at least $40000,
-50x² + 3500x - 2500 ≥ 40000
-50x² + 3500x ≥ 40000 + 2500
-50x² + 3500x ≥ 42500
-x² + 70x ≥ 850
x² - 70x + 850 ≤ 0
By quadratic formula,
x - intercept of the inequality will be,
x =
x =
x = 15.635, 54.365
Therefore, $15.635 ≤ x ≤ $54.365 will be the range of cost for which profit will be at least $40000.