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Charra [1.4K]
3 years ago
10

4. Kay and Allen sell cell phones. Last month Kay sold 17 more cell phones than Allen. Together they both sold 117 cell phones.

How many phones did each of them sell individually? Show the equation you used to determine the answers
Mathematics
2 answers:
forsale [732]3 years ago
7 0

Answer:

Allen sold 50 cell phones while Kay sold 67 cell phones.

Step-by-step explanation:

Let the number of cell phones sold by Allen be x. This will imply that the number of cell phones sold by Kay is x + 17.

Furthermore, we are informed that together they sold a total of 117 cell phones. Therefore, we use the following equation to determine the number of cell phones sold by each;

x + x + 17 = 117

2x + 17 = 117

2x = 100

x = 50

Therefore, Allen sold 50 cell phones while Kay sold 67 cell phones.

mina [271]3 years ago
3 0

Answer:

Equations: x = y + 17  and x + y =  117

Kay sold 67 cell phones and Allen sold 50 cell phones.

Step-by-step explanation:

Let the number of cell phones sold by Kay be "x" and the number of cell phones sold by Allen be "y"

According to the given statement Kay sold 17 more cell phones than Allen. This means, x would be 17 larger than y. In equation this can be represented as:

x = y + 17                                                     Equation 1

Together they sold 117 cell phones. This means, sum of x and y would be 117. In equation this would be:

x + y =  117                                                   Equation 2

Above two equations can be used to determine the number of cell phones sold by Kay and Allen.

Using value of x from Equation 1 into Equation 2, we get:

y + 17 + y = 117

2y = 117 - 17

2y = 100

y = 50

Using the value of y in Equation 1, we get:

x = 50 + 17 = 67

This means, Kay sold 67 cell phones and Allen sold 50 cell phones.

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\fbox{\begin{minipage}{16em}Option D: y = (4/7)x + 8 is correct\end{minipage}}

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