Answer:
Step-by-step explanation:
<u>Given Data:</u>
Base area = 
= 108 in.²
Volume = V = 729 in.³
<u>Required:</u>
Height = h = ?
<u>Formula:</u>
<u>Solution:</u>
For h, rearranging formula:
![\displaystyle h = \frac{V}{A_{B}} \\\\h =\frac{729 \ in.^3}{108 \ in.^2} \\\\h = 6.75 \ in.\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20h%20%3D%20%5Cfrac%7BV%7D%7BA_%7BB%7D%7D%20%5C%5C%5C%5Ch%20%3D%5Cfrac%7B729%20%5C%20in.%5E3%7D%7B108%20%5C%20in.%5E2%7D%20%5C%5C%5C%5Ch%20%3D%206.75%20%5C%20in.%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Answer:
I belive it is 105
Step-by-step explanation:
ok so by spliting this up into where the 9 lengh ends.that recctangle is now 9 by 6,to find area you multiply them,that gets you 54.Now for the other part you want to fill it in,when you do that the area is 6 by 11 what equals 66 but ou have to take away the corner making it 51.Now we add those together and you have 105.
Answer: that's hard
Step-by-step explanation:that's hard
The value of the Nintendo after 35 years is $2455
Since the formula f(x) = 3x² - 40x + 180 predicts the value of the Nintendo x years after 1986.
Since we require the value in 2021, x years after 1986 is 2021 - 1986 = 35 years.
Substituting x = 35 into the equation, we have
f(x) = 3x² - 40x + 180
f(x) = 3(35)² - 40(35) + 180
f(x) = 3(1225) - 40(35) + 180
f(x) = 3675 - 1400 + 180
f(x) = 2275 + 180
f(x) = 2455
So, the value of the Nintendo after 35 years is $2455
Do you think this is a realistic prediction of the value of that Nintendo?
This is not a realistic prediction for the value of the Nintendo, because, it is too high.
Learn more about quadratic equations here:
brainly.com/question/13704125
Answer:
Step-by-step explanation:
The expression to transform is:
![(\sqrt[6]{x^5})^7](https://tex.z-dn.net/?f=%28%5Csqrt%5B6%5D%7Bx%5E5%7D%29%5E7)
Let's work first on the inside of the parenthesis.
Recall that the n-root of an expression can be written as a fractional exponent of the expression as follows:
![\sqrt[n]{a} = a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Therefore ![\sqrt[6]{a} = a^{\frac{1}{6}}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7Ba%7D%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D)
Now let's replace 
with 
which is the algebraic form we are given inside the 6th root:
![\sqrt[6]{x^5} = (x^5)^{\frac{1}{6}}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7Bx%5E5%7D%20%3D%20%28x%5E5%29%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D)
Now use the property that tells us how to proceed when we have "exponent of an exponent":
Therefore we get: 
Finally remember that this expression was raised to the power 7, therefore:
^7=(x^\frac{5}{6})^7=x^\frac{35}{6}](https://tex.z-dn.net/?f=%5Btex%5D%28%5Csqrt%5B6%5D%7Bx%5E5%7D%29%5E7%3D%28x%5E%5Cfrac%7B5%7D%7B6%7D%29%5E7%3Dx%5E%5Cfrac%7B35%7D%7B6%7D)
[/tex]
An use again the property for the exponent of a exponent:
