One question please help a friend out thanks you guys :-)

Write down the first even multiple of 7.

user100 [1]

Answer:

3.5

Step-by-step explanation:

5 0

3 years ago

A music producer is making a list of vocalists needed to record an album. For each day of recording, a different number of vocal

Pani-rosa [81]

Answer:

6,138

Step-by-step explanation:

Given the following:

Vocalist needed :

First day (a) = 6

For subsequent days : number doubles

Using the relation. :

Sn = a(r^n -1)/(r -1)

Where a = first term = 6

r = common ratio = r3/r2 = r4/r3

Since number doubles after each consecutive day, then ; r = 2, n = 10

Sn = 6(2^10 -1)/(2 -1)

Sn = 6(1024 - 1) / 1

Sn = 6144 - 6

Sn = 6138

3 0

3 years ago

Write an equation in slope-intercept form for the line that has a slope of -4 and passes through (1, 2).

Svetradugi [14.3K]

y-y1 = m(x-x1) ..... point slope form

y-2 = -4(x-1) ... plug in the given info; solve for y

y-2 = -4x+4

y = -4x+4+2

y = -4x+6

Answer is choice C

5 0

3 years ago

Read 2 more answers

1. M is the midpoint of LN and O is the midpoint of NP.

Reptile [31]

1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP

If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8

2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2

Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4

FC= 2/(1+2) * AC
FC= 2/3 * 12= 8

3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2

DC=3x+12= 3(-2) +12= 6

4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3

C
BC lines slope would be (-1)-(-1)/4 = 0/4.
The line would be
0=x+a
a=-1
0=x-1
x=1

y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1

y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)

5.
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines

5 0

3 years ago

Sakura speaks 150150150 words per minute on average in Hungarian, and 190190190 words per minute on average in Polish. She once

d1i1m1o1n [39]

Answer:

300 words in Hungarian and 570 in Polish.

Step-by-step explanation:

I guess you need to know the number of words in Hungarian and in Polish.

Let H be the words he said in Hungarian, and P the words he said in Polish.

We are told that Sakura uttered a total of 270 more words in Polish than in Hungarian, therefore:

P = H + 270

And that I speak for 5 minutes, we know that the speed of words in Hungarian is 150 and in Polish it is 190, therefore:

5 = H / 150 + P / 190

Thus we have two equations and two unknowns, that is, it has a solution, replacing P:

5 = H / 150 + (H +270) / 190

5 = (190 * H + 150 * H + 270 * 150) / (150 * 190)

5 * 150 * 190 = 340 * H + 270 * 150

H = (5 * 150 * 190 - 270 * 150) / 340

H = 300

Therefore he said 300 words in Hungarian.

In Polish it would be:

P = 300 + 270 = 570

To check we have to:

300/150 + 570/190 = 5

Therefore, Sakura giving the instructions said 300 words in Hungarian and 570 in Polish.

8 0

3 years ago