Since he must not exceed 8 hours driving in a day: Let the distance of the picnic be = x km.
Therefore time for forward journey = x / 60 Return journey = x / 50
The total trip should not exceed 8 hours. Therefore: x / 60 + x / 50 <= 8. LCM = 300
Taking LCM and multiplying on both sides: 5x + 6x <= 8(300) 11x <= 2400 x <= 2400/11 x <= 218.18 The picnic spot must be less than or equal to 218.18 km.